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OleMash [197]
3 years ago
10

6x + y = 5, slope intercept form.

Mathematics
2 answers:
Tju [1.3M]3 years ago
7 0
6x + y = 5
Subtract the 6x
y = -6x + 5
And that’s all :) hope it helps
rosijanka [135]3 years ago
4 0
Slope intercept form is y= mx+ b so your answer is

y=-6x+5
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Express 2x^2+8x+3 in the form 2(x+p)^2+q
e-lub [12.9K]

Answer:

2(x + 2)² - 5

Step-by-step explanation:

Given

2x² + 8x + 3

To obtain the required form use the method of completing the square.

The coefficient of the x² term must be 1, thus factor 2 out of 2x² + 8x

= 2(x² + 4x) + 3

add/subtract ( half the coefficient of the x- term)² to x² + 4x

= 2(x² + 2(2)x + 4 - 4) + 3

= 2(x + 2)² - 8 + 3

= 2(x + 2)² - 5

with p = 2 and q = - 5

4 0
3 years ago
When estimating a job to bid, a contractor’s estimator first determines the actual cost of labor using the function L(h) = 28.75
dybincka [34]

Answer:

  M(h) = 73.18025h

Step-by-step explanation:

The composite function is ...

  M(B(L(h))) = M(B(28.75h)) = M(1.78(28.75h)) = M(51.175h)

  = 1.43(51.175h) = 73.18025h

The composite function is ...

  M(h) = M(B(L(h))) = 73.18025h

7 0
3 years ago
The scale on a map is 1:500000 two towns are 7cm apart
Eddi Din [679]
7 x 500,000 = 3,500,000.

The towns are 3,500,000 units apart (I don't know what the cm were scale too, sorry.)
7 0
3 years ago
Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu
tia_tia [17]

Answer:

The minimum head breadth that will fit the clientele is 4.4 inches.

The maximum head breadth that will fit the clientele is 7.8 inches.

Step-by-step explanation:

Let <em>X</em> = head breadths of men that is considered for the helmets.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 6.1 and standard deviation, <em>σ</em> = 1.

To compute the probability of a normal distribution we first need to convert the raw scores to <em>z</em>-scores using the formula:

z=\frac{x-\mu}{\sigma}

It is provided that the helmets will be designed to fit all men except those with head breadths that are in the smallest 4.3% or largest 4.3%.

Compute the minimum head breadth that will fit the clientele as follows:

P (X < x) = 0.043

⇒ P (Z < z) = 0.043

The value of <em>z</em> for this probability is:

<em>z</em> = -1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.717=\frac{x-6.1}{1}\\x=6.1-(1.717\times 1)\\x=4.383\\x\approx4.4

Thus, the minimum head breadth that will fit the clientele is 4.4 inches.

Compute the maximum head breadth that will fit the clientele as follows:

P (X > x) = 0.043

⇒ P (Z > z) = 0.043

⇒ P (Z < z) = 1 - 0.043

⇒ P (Z < z) = 0.957

The value of <em>z</em> for this probability is:

<em>z</em> = 1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\1.717=\frac{x-6.1}{1}\\x=6.1+(1.717\times 1)\\x=7.817\\x\approx7.8

Thus, the maximum head breadth that will fit the clientele is 7.8 inches.

5 0
3 years ago
99 newspapers in 3 piles
monitta

Answer:

33 newspapers per 1 pile.

Step-by-step explanation:

33+33+33=99

5 0
3 years ago
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