The answer i think is. If<span> the </span>length<span> of the </span>table<span> is </span>18 ft more than<span> the </span>width<span>, </span>x, which - 1447102. ... Thearea<span> of the </span>conference table<span> in </span>Mr<span>. </span>Nathan's office must<span> be </span>no more than 175 ft2<span> ... Therefore, the</span>interval<span> 0 < </span>x<span> ≤ 7 represents the possible widths</span>
3500(1 + .03/12)^12(5)
3500(1.0025)^60
The answer is:
$4,065.66 or $4,066
Hope this helps :)
Answer:
x=13,y=0
Step-by-step explanation:
We are given a system of equations

For equation 1,square all terms to reduce it
√x²+√y²=169
x+y=13
Make x the subject as required by the question to use substitution method
x=13-y
Plug x=13-y into eqn 2
3(13-y)+2y=39
39-3y+2y=39
39-y=39
y=39-39=0
Plug y=0 into equation 1
x+0=13
x=0
Answer:
I would increase the number and multiply
Step-by-step explanation:
Answer:
It is the third one because of formula I² + 2I*II + II²
In your case I = 4x and II = 3