Ok so student in cleveland walks 2.5 miles away from cleveland every hour from 8
so the distance, x is x=2.5t
the riding one rides 4 hours later, so t-4
11 mph
y=11(t-4)
A. x=2.5t
y=11(t-4)
when do they meet is when the distance when they are equal or when x=y
2.5t=x=y=11(t-4)
solve for t
2.5t=11(t-4)
2.5t=11t-44
-8.5t=-44
divide both sides by -8.5
t=5.17647
answer is 5.18 hours
A.
x=2.5t
y=11(t-4)
B. 5.18 hours
5/6 im guessing ? Im pretty sure its 5:6
Answer:
(D) 29.3
Step-by-step explanation:
The answer is all the days added together and then divided by 10.
20+30+40+38+25+22+39+22+26+31=293.
293/10=29.3
Answer:
about 20
Step-by-step explanation:
its kindergarden math
