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3 years ago

OMG HELP ME find the angles then list them from least to greatest

Mathematics

2 answers:

Musya8 [376]3 years ago

5 0

Yeah. i think you have to solve for the variables before we are able to help you

7nadin3 [17]3 years ago

4 0

U need to add them all together

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Microsort is a genetics company that advertises a product that supposedly increases the chance of a female birth for couples pla

Brut [27]

The correct answer is C

8 0

3 years ago

19x+rx=-37+w <br><br><br> solve for x

ipn [44]

Factor the left side:-

x (19 + r) = -37 + w

x = ( -37 + w) / (19 + r) Answer

3 0

3 years ago

Read 2 more answers

we need to check to see if 27 to the second power + 45 to the second power equals 36 to the second power is a true statement the

Yuri [45]

Answer:

Thx for the points

Step-by-step explanation:

3 0

3 years ago

Question 5 (25 points)

DiKsa [7]

Answer:

Again its C like i answered before.

Step-by-step explanation:

Cos is adj/hyp and there is only one cos option so it must be correct.

7 0

3 years ago

Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1

Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

P.Q. = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean = 101

$\sigma$ = population standard deviation

n = sample size = 25

So, 90% confidence interval for the population mean test score, $\mu$ is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.6449) = 0.90

P(-1.6449 * $\frac{\sigma}{\sqrt{n} }$ < ${Xbar-\mu}$ < 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

P(X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ < $\mu$ < X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

90% confidence interval for $\mu$ = [ X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ , X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ]

= [ 101 - 1.6449 * $\frac{17}{\sqrt{25} }$ , 10 + 1.6449 * $\frac{17}{\sqrt{25} }$ ]

= [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0

4 years ago