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ella [17]
2 years ago
7

we need to check to see if 27 to the second power + 45 to the second power equals 36 to the second power is a true statement the

left side of the equation is equal to 2754 the right side of the equation is equal to 1296 that means that 27 to the second power + 45 to the second power equals 36 to the second power is not true and the triangle shown is not a right triangle​
Mathematics
1 answer:
Yuri [45]2 years ago
3 0

Answer:

Thx for the points

Step-by-step explanation:

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A square is cut into three equal rectangles. How does the area of the square compare to the sum of the areas of the three rectan
ludmilkaskok [199]

Answer:

A?

Step-by-step explanation:

If the square was split into 3 rectangles the 3 rectangles sum up to the square.

4 0
2 years ago
PLEASE Please answer ASAP!!! :)
d1i1m1o1n [39]

Answer: No it is not.

Step-by-step explanation: A rational number is a number that can easily be expressed as a fraction or decimal, and square root of 7 cannot be easily expressed.

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2 years ago
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erastova [34]

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3 years ago
What is 72 ounce in 2 steaks as a unit rate
Ilya [14]
The unit rate in this scenario is the number of ounces per steak/in one steak.

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3 0
3 years ago
Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).
storchak [24]

Answer:

P=16.53\ units

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(2-2)^{2}}

d=\sqrt{(-1)^{2}+(0)^{2}}

d=\sqrt{1}

dPQ=1\ unit

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

dQR=\sqrt{41}\ units

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

d=\sqrt{(3+2)^{2}+(-2+2)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

dRS=5\ units

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

d=\sqrt{(3-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-1)^{2}+(-4)^{2}}

dPS=\sqrt{17}\ units

step 5

Find the perimeter

P=PQ+QR+RS+PS

substitute the values

P=1+\sqrt{41}+5+\sqrt{17}

P=6+\sqrt{41}+\sqrt{17}

P=16.53\ units

5 0
3 years ago
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