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mojhsa [17]
3 years ago
14

If a number is added yo the numerator of 12/43 and twice the number is added to the denominator of 12/43 the resuliting fraction

is equivalent to 1/3 find the number
Mathematics
2 answers:
DaniilM [7]3 years ago
3 0

Answer:

The number is 7.

Step-by-step explanation:

In this case we have an unkown variable that is a number. We will call this number by "x", this is what we want to calculate. In the first part it is said that the number or x is added to the numerator and in the second part it is said that twice the number is added to the denominator, and that this fraction is equal to 1/3. So we have:

1/3 = (12 + x)/(43 + 2*x)

43 + 2*x = 3*(12 + x)

43 + 2*x = 36 + 3*x

43 - 36 = 3*x - 2*x

x = 7

The number is 7.

Fiesta28 [93]3 years ago
3 0

Answer: 7

Step-by-step explanation:

Let the number be X

When number is added to the numerator of 12/43, the number is 12+X/43 and twice the number is added to the denominator of 12/43, this will give 12+X/43+2X, the resuliting fraction is equivalent to 1/3. Mathematically, this will be

12+X/43+2X = 1/3

Cross multiply

3(12+X) = 43+2X

36+3X= 43+2X

Collected like terms

3X-2X = 43-36

X= 7

The number is 7

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If YX=YZ, X is 9x-23 and Z is 4x+9 find Z?
Zina [86]

Answer:

6.4

Step-by-step explanation:

9x-23=4x+9

5x=32

x=6.4

If I'm right, brainliest pls?

5 0
3 years ago
Five units to the right of -6
Galina-37 [17]

Answer: -1

Step-by-step explanation:

3 0
3 years ago
the diagonals PR and QS of a rhombus intersect each other at point O. prove that 2(PQ) + 2(RS) + 2(RS)+ 2(PS) = 4 (2(OP)+2(OQ))
Svetllana [295]

Answer:

6 is the answer

Step-by-step explanation:

3 0
3 years ago
Ten items are to be sampled from a lot of 60. If more than one is defective, the lot will be rejected. Find the probability that
stellarik [79]

Answer:

(a) The probability of that the lot will be rejected is 0.1904.

(b)The probability of that the lot will be rejected is 0.5315 .

(c)The probability of that the lot will be rejected is 0.7026.

Step-by-step explanation:

The formula of Hypergeometric distribution is

P(X=x)=\frac{(^{R}C_x)( ^{N-R}C_{n-x})}{^NC_n}

N= number of population

R= The number of success event

n= sample of size

(a)

Given that, N=  60, R=5 and n=10

More than 1 is defected, the lot will be rejected.

X is random variable and defined the number of rejected item.

P(X>1)=1-P(X≤1)

        =1 - P(X=0) - P(X=1)

        =1- \frac{(^5C_0)(^{60-5}C_{10-0})}{^{60}C_{10}}-\frac{(^5C_1)(^{60-5}C_{10-1})}{^{60}C_{10}}

        =1 - 0.3879 - 0.4217

          =0.1904

The probability of that the lot will be rejected is 0.1904.

(b)

N=  60, R=10 and n=10

X is random variable and defined the number of rejected item.

P(X>1)=1-P(X≤1)

        =1 - P(X=0) - P(X=1)

        =1- \frac{(^{10}C_0)(^{60-10}C_{10-0})}{^{60}C_{10}}-\frac{(^{10}C_1)(^{60-10}C_{10-1})}{^{60}C_{10}}

       =1-0.1362-0.3323

      =0.5315

The probability of that the lot will be rejected is 0.5315 .

(c)

N=  60, R=20 and n=10

X is random variable and defined the number of rejected item.

P(X>1)=1-P(X≤1)

        =1 - P(X=0) - P(X=1)

        =1- \frac{(^{20}C_0)(^{60-20}C_{10-0})}{^{60}C_{10}}-\frac{(^{20}C_1)(^{60-20}C_{10-1})}{^{60}C_{10}}

       =1 -0.2249 - 0.0725

       =0.7026

The probability of that the lot will be rejected is 0.7026.

4 0
3 years ago
Susie has 5/8ths of a gallon of tea and needs to fill as many glasses as possible. If each glass holds 2/7ths of a cup, how many
Klio2033 [76]

Answer:

35 glasses

Step-by-step explanation:

Susie has 5/8 gallon = 5/8 * 16 = 10 cups

10 cups ÷ 2/7 cups per glass = 35 glasses

7 0
2 years ago
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