First, we need to know how many things between 1 and 50 are divisible by 3, this would be 16. Then we would divide this by the total number of integers, 16/50=8/25. This means your answer is C.
122.
The numbers are multiplied by -3 every time, so the fifth term would be 162, then you add the numbers all together to make 122.
<span>There are several possible events that lead to the eighth mouse tested being the second mouse poisoned. There must be only a single mouse poisoned before the eighth is tested, but this first poisoning could occur with the first, second, third, fourth, fifth, sixth, or seventh mouse. Thus there are seven events that describe the scenario we are concerned with. With each event, we want two particular mice to become diseased (1/6 chance) and the remaining six mice to remain undiseased (5/6 chance). Thus, for each of the seven events, the probability of this event occurring among all events is (1/6)^2(5/6)^6. Since there are seven of these events which are mutually exclusive, we sum the probabilities: our desired probability is 7(1/6)^2(5/6)^6 = (7*5^6)/(6^8).</span>
Answer: V≈900 ft³
Step-by-step explanation:
Formula
V=πr²h
Given
r=5 ft
h=12 ft
Solve
V=πr²h
V=π(5)²(12)
V=π(25)(12)
V=300π
V≈300(3)
V≈900 ft³
Hope this helps!! :)
Please let me know if you have any questions
Answer:
your right
Step-by-step explanation:
