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babunello [35]
3 years ago
11

Find the number of ordered pairs $(m,n)$ of integers that satisfy \[mn = 2m + 4n.\]

%20number%20of%20ordered%20pairs%20%24%28m%2Cn%29%24%20of%20integers%20that%20satisfy%20%5C%5Bmn%20%3D%202m%20%2B%204n.%5C%5D" id="TexFormula1" title="Find the number of ordered pairs $(m,n)$ of integers that satisfy \[mn = 2m + 4n.\]" alt="Find the number of ordered pairs $(m,n)$ of integers that satisfy \[mn = 2m + 4n.\]" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Anna35 [415]3 years ago
5 0

There are four pairs (m,n) that work: (5,10), (6,6), (8,4), and (12,3).

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Step-by-step explanation:

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therefore 73+s = 120

so 120- s = 73

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1 and 5/6 + 2 and 2/11
lions [1.4K]
1 \frac{5}{6} +2 \frac{2}{11} =\frac{(1\times6)+5}{6} +\frac{(2\times 11)+2}{11} =\frac{11}{6}+\frac{24}{11} \\\\=\frac{11\times 11}{6\times 11} +\frac{24\times6}{11\times6} =\frac{121}{66} +\frac{144}{66}=\frac{121+144}{66} =\frac{265}{66}\\\\=\boxed{\bf{4\frac{1}{66}}}
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