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3 years ago

8

An item is regularly priced at $15. It is now priced at a discount of 55% off the regular price.

1 answer:

Verdich [7]3 years ago

6 0

If it is marked at 55% off, the u r actually paying 45%

so 45% of 15 = 0.45(15) = 6.75 <== discounted price

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What is absolute value?

pochemuha

Answer:

Absolute value means the distance between a number and 0.

Examples:

The absolute value of -7 is 7.

The absolute value of 5 is 5.

Key Concepts:

The absolute value sign is |x|, where x is any real number.

The absolute value removes any negative sign in front of a number.

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3 years ago

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Y=-2x graphed. had to put more words to put this out

timurjin [86]

Slope-intercept form:

y = mx + b

"m" is the slope, "b" is the y-intercept (the y value when x = 0, or (0,y))

$slope=\frac{rise}{run}$

Rise is the number of units you go up(+) or down(-)

Run is the number of units you go to the right

y = -2x

This has a y-intercept of 0, so the line intersects the y-axis/goes through the origin at (0,0)

The slope is -2 or $\frac{-2}{1}$ , so from each point, you go down 2 units, and to the right 1 unit.

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3 years ago

What is the length of the hypotenuse of the triangle?

sergeinik [125]

17

This is gonna be confusing but this is how you solve stuff like this

8 x 8 = 64 15 x 15 = 225
64 + 225 = 289
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3 0

3 years ago

A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

mestny [16]

Answer:

The value is $W= 2640 \ ft \cdot lb$

Step-by-step explanation:

From the question we are told that

The weight of the bucket is $F = 5 lb$

The depth of the well is $x_1 = 60 \ ft$

The weight of the water is $W_w = 42 lb$

The rate at which the bucket with water is pulled is $v = 1.5 \ ft/s$

The rate of the leak is $r = 0.15 lb/s$

Generally the workdone is mathematically represented as

$W = \int\limits^{x_1}_{x_o} {G(x)} \, dx$ ]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

$G(x) = F + (W_w- Ix)$

Here I is the rate of water loss in lb/ft mathematically represented as

$I = \frac{r}{v}$

=> $I = \frac{0.15 }{1.5 }$

=> $I = 0.1$

So

$G(x) = 5 + (42- 0.1x)$

=> $G(x) = 47- 0.1x)$

So

$W = \int\limits^{60}_{0} {47- 0.1x} \, dx$ ]

=> $W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.$

=> $W= [47(60) - 0.05(60)^2]$

=> $W= 2640 \ ft \cdot lb$

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3 years ago

What is the solution to log (9x)-log2^3= 3?

olga_2 [115]

For this case we have that by definition of properties logarithm is met:

$log_ {b} (x) -log_ {b} (y) = log_ {b} (\frac {x} {y})$

So, rewriting the expression we have:

$log (\frac {9x} {2 ^ 3}) = 3\\log (\frac {9x} {8}) = 3$

By definition of logarithm we have to:

$log_ {b} (x) = y$ is equivalent to $b ^ y = x$

So:

$10 ^ 3 = \frac {9x} {8}\\9x = 8 * 10 ^ 3\\9x = 8 * 1000\\9x = 8000\\x = \frac {8000} {9}$

ANswer:

$x = \frac {8000} {9}$

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3 years ago

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