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Tanzania [10]
3 years ago
15

What is the value of y in the solution to the following system of equations?

Mathematics
1 answer:
tresset_1 [31]3 years ago
4 0
For the answer to the question above,
2x+ y = -4       5x + 3y = -6
y= -4 -2x    

substitute y=-4-2x into 5x+3y=-6
5x + 3(-4-2x) = -6
5x -12 -6x =-6
-x=6
x=-6

sub x=-6 into 2x+y=-4
-12 + y = -4
y=8

x=-6 and y=8
I hope my answer helped you.
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D 1/10

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Subject: Mathematics
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\\ \sf\longmapsto \dfrac{1}{x-1}>4

  • Multiply x-1 on both sides

\\ \sf\longmapsto \dfrac{1}{x-1}\times (x-1)> 4(x-1)

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\\ \sf\longmapsto 1> 4x-4

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\\ \sf\longmapsto 1+4> 4x

\\ \sf\longmapsto 5> 4x

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\\ \sf\longmapsto \dfrac{5}{4}>x

\\ \sf\longmapsto x< \dfrac{5}{4}

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ATQ to the equation \bf \dfrac{1}{x-1} x should be greater than 1 .Because if it becomes 1 then the denominator will be 0 which is impossible.

Hence x>1

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\\ \sf{:}\!\implies 1

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\\ \therefore\boxed{\bf x\epsilon \left(1,\dfrac{5}{4}\right)}

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