a ) The domain:
x^4 - 16 x² ≥ 0
x² ( x² - 16 ) ≥ 0
x² - 16 ≥ 0
x² ≥ 16
x ∈ ( - ∞, - 4 ] ∪ [ 4 , + ∞ )b ) f ` ( x ) =
=
( 2 x³ - 16 x ) / √(x^4 - 16 x²)c ) The slope of the tangent line at x = 5:
f ` ( 5 ) = ( 2 * 125 - 16 * 5 ) / √ ( 625 - 400 ) = 170 / 15 = 34 / 3
The slope of the line normal to the graph at x = 5:
m = - 3 / 34
Answer: a
Step-by-step explanation:
Answer:
It will be no solution the reason is you have to subtract 3x from both sides and the simplify -7=1
Step-by-step explanation:
Answer:
Diagram attached
AJ = 8.75 in.
Step-by-step explanation:
Since triangles HBA & HKJ are similar,
BH/AH = KH/JH
3 in /5.25 in = 8 in /JH
JH = 14 in
JA = JH - AH = JH - 5.25 in = 8.75 in
HJ = 14 in.
AJ = 14 in - 5.25 in
AJ = 8.75 in.
