Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
Answer: -1
Step-by-step explanation:
Answer:
A. at least two congruent sides
Step-by-step explanation:
Since, we know that,
'An isosceles triangle is a triangle having two sides of equal length or at least two sides of equal length (special case is equilateral triangle)'.
Thus, from the options, we see that,
Options B, C and D are not correct.
<em>Since, congruent sides means that the lengths of the sides are equal.</em>
Thus, we get that,
'An isosceles triangle has at least two congruent sides'.
Hence, option A is correct.
Multiply 3x9 and it gives u 27
And -3 plus -9 equal -12
Answer:
Step-by-step explanation:
To distribute means to multiply everything outside the parenthesis with everything inside the parenthesis, so in this case 7x8 then 7(x) then 7x2 so that is equal to 56 + 7x + 14, so combine the 56+14 so we get 7x + 70. I hope '7' is part of the problem and not the question number
