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Aleks [24]
3 years ago
7

N+12=4 what is the process of the equation

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
6 0

Hey there!

Here is your question -

n+12=4

In this equation, you're looking for n alone. To keep the variable alone, you have to do the opposite of what's happening to the variable.

In this equation, 12 is being added to n. The opposite of that is subtracting 12.

Subtract 12 from both sides -

n+12-12=4-12 \\ n=-8

Your answer is -8.

Hope this helps! :)

irinina [24]3 years ago
4 0

Answer:

the process is in the step by step explanation

Step-by-step explanation:

12-4=8

n=8

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Step-by-step explanation:

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7 0
3 years ago
The initial population of a town is 1,300 and it is increasing at the rate of 3% each year. Find the population at 12 years​
stepan [7]

Answer:

1300 * (1 + 0.03)^12 = 1853

7 0
3 years ago
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A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of
GenaCL600 [577]

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.989.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

8 0
3 years ago
A miniature quadcopter is located at xi = −1.75 m and yi = −5.70 m at t = 0 and moves with an average velocity having components
Black_prince [1.1K]

The quadcopter's average velocity is given in terms of change in position by

\vec v_{\rm av}=\dfrac{\Delta x}{\Delta t}\,\vec\imath+\dfrac{\Delta y}{\Delta t}\,\vec\jmath

where \Delta x=x_f-x_i, the difference in the quadcopter's final and initial positions and \Delta t=(1.60-0)\,\mathrm s=1.60\,\mathrm s.

The x-component of the average velocity is 2.70 m/s, so

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and the y-component is -2.50 m/s, so

-2.50\dfrac{\rm m}{\rm s}=\dfrac{y_f-(-5.70\,\mathrm m)}{1.60\,\rm s}\implies\boxed{y_f=-9.70\,\mathrm m}

4 0
3 years ago
1. which of these numbers is divisible by 12?
Gala2k [10]
1. 6 is the answer
2. 56 is divisible by 14
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