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timofeeve [1]
3 years ago
14

I need to simplify this

Mathematics
2 answers:
Igoryamba3 years ago
8 0
-7-i+6-3i= (-7+6)+(-i-3i)= -1 - 4i
Anon25 [30]3 years ago
3 0
Your answer would be
-7-(-i)+6-3i
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Estimate the Product of 58 and 16
Tanzania [10]

Answer:

928

Step-by-step explanation:

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Angle x is conterminal with angle y. If the measure of angle x is greater than the measure of angle y, which statement is true r
fiasKO [112]

9514 1404 393

Answer:

  x = y + 360n, for any positive integer n

Step-by-step explanation:

Since x is greater than y, something must be added to y to get x. Angles have the same co-terminal ray at multiples of 360°. Then the amount added to y must be some multiple of 360°:

  x = y + 360n . . . . . for positive integer n

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3 years ago
Convert the rectangular equation, 3x − y = 6 , to a polar equation that expresses r in terms of θ.
Yakvenalex [24]
The answer would be 21
5 0
3 years ago
A) Use the limit definition of derivatives to find f’(x)
Ann [662]
<h3>1)</h3>

\text{Given that,}\\\\f(x) =  \dfrac{ 1}{3x-2}\\\\\text{First principle of derivatives,}\\\\f'(x) = \lim \limits_{h \to 0} \dfrac{f(x+h) - f(x) }{ h}\\\\\\~~~~~~~~= \lim \limits_{h \to 0} \dfrac{\tfrac{1}{3(x+h) - 2} - \tfrac 1{3x-2}}{h}\\\\\\~~~~~~~~= \lim \limits_{h \to 0}  \dfrac{\tfrac{1}{3x+3h -2} - \tfrac{1}{3x-2}}{h}\\\\\\~~~~~~~~= \lim \limits_{h \to 0} \dfrac{\tfrac{3x-2-3x-3h+2}{(3x+3h-2)(3x-2)}}{h}\\\\\\

       ~~~~~~~= \lim \limits_{h \to 0} \dfrac{\tfrac{-3h}{(3x+3h-2)(3x-2)}}{h}\\\\\\~~~~~~~~= \lim \limits_{h \to 0} \dfrac{-3h}{h(3x+3h-2)(3x-2)}\\\\\\~~~~~~~~=-3 \lim \limits_{h \to 0} \dfrac{1}{(3x+3h-2)(3x-2)}\\\\\\~~~~~~~~=-3 \cdot \dfrac{1}{(3x+0-2)(3x-2)}\\\\\\~~~~~~~~=-\dfrac{3}{(3x-2)(3x-2)}\\\\\\~~~~~~~=-\dfrac{3}{(3x-2)^2}

<h3>2)</h3>

\text{Given that,}~\\\\f(x) = \dfrac{1}{3x-2}\\\\\textbf{Power rule:}\\\\\dfrac{d}{dx}(x^n) = nx^{n-1}\\\\\textbf{Chain rule:}\\\\\dfrac{dy}{dx} = \dfrac{dy}{du} \cdot \dfrac{du}{dx}\\\\\text{Now,}\\\\f'(x) = \dfrac{d}{dx} f(x)\\\\\\~~~~~~~~=\dfrac{d}{dx} \left( \dfrac 1{3x-2} \right)\\\\\\~~~~~~~~=\dfrac{d}{dx} (3x-2)^{-1}\\\\\\~~~~~~~~=-(3x-2)^{-1-1} \cdot \dfrac{d}{dx}(3x-2)\\\\\\~~~~~~~~=-(3x-2)^{-2} \cdot 3\\\\\\~~~~~~~~=-\dfrac{3}{(3x-2)^2}

8 0
2 years ago
#6 math help fun please?
julsineya [31]

Answer:

mean: 27.6

median: 32

mode: 35

range: 35

Step-by-step explanation:

Definitions:

mean: average

median: middle

mode: the number that comes up the most

range: the difference between the highest and lowest values/numbers

What to do:

mean: you add up all the numbers and then you divide that sum by the amount of numbers there are (I'm not going to do the work because that's a lot of numbers to type out, but you can check your work with my answer).

~answer is 27.6

median: middle number --> 32

mode: the number that comes up the most --> 35

range: 40-5 = 35

4 0
3 years ago
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