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Leni [432]
3 years ago
14

4.

Mathematics
1 answer:
Arlecino [84]3 years ago
6 0

Answer:

66

Step-by-step explanation:

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The mean height of a group of 500 nonsmoking college students is 74 inches and the standard deviation is 5 inches. What is the p
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500 (non smokers)÷ 25(random students out of the group)= 20 inches. 20 inches ÷ 74 inches= 3.70
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Is -¼ + 2 ¼y + 2 - y equivalent to y + 2 ?
Juliette [100K]

Answer: No

Step-by-step explanation:

-\frac{1}{4}+2\frac{1}{4}y+2-y=y+2

(-\frac{1}{4}+2)+(2\frac{1}{4}y-y)=y+2\\

(\frac{(-1)+(4)(2)}{4})+(\frac{9}{4}y-y)=y+2

(\frac{-1+8}{4})+(\frac{(9)(1)-(4)(1)}{4} )y=y+2

(\frac{7}{4})+(\frac{9-4}{4} )y=y+2

(\frac{7}{4})+(\frac{5}{4})y=y+2

5 0
3 years ago
An exit poll in an election is a survey taken of voters just after they have voted. One major use of exit polls has been so that
3241004551 [841]

Answer:

P(A) = 0.39

Step-by-step explanation:

We are given;

P(W|A) = 0.7

P(W|A^c ) = 0.3

We are told that 60% of the respondents said they voted for A. Thus;

P(A|W) = 60% = 0.6

Now, using the principle of drawing lots, we can be able to find the probability of the event that they are willing to participate in the exit poll which is P(W).

Thus;

P(W) = [P(W|A) × P(A)] +[P(W∣A^c) × P(A^c)]

Now, P(A^c) can be expressed as 1 - P(A)

Thus, we now have;

P(W) = [P(W|A) × P(A)] + [P(W∣A^c) × (1 - P(A)]

Plugging in the relevant values gives;

P(W) = 0.7P(A) + 0.3(1 - P(A))

P(W) = 0.7P(A) + 0.3 - 0.3P(A)

P(W) = 0.3 + 0.4P(A)

Now,using Baye's theorem, we can find an expression for P(A|W)

Thus;

P(A|W) = [P(A ∩ W)]/P(W)

This can be further expressed as;

P(A|W) = [P(A) × P(W|A)]/P(W)

Plugging in relevant values, we have;

0.6 = 0.7P(A)/(0.3 + 0.4P(A))

Cross multiply to get;

0.6(0.3 + 0.4P(A)) = 0.7P(A)

0.18 + 0.24P(A) = 0.7P(A)

0.18 = 0.7P(A) - 0.24P(A)

0.46P(A) = 0.18

P(A) = 0.18/0.46

P(A) = 0.39

7 0
3 years ago
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