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OLEGan [10]
3 years ago
11

25% of 60 10% of 150 Are these amounts equivalent?

Mathematics
1 answer:
baherus [9]3 years ago
4 0

Answer:

Yes, they are equivalent

Step-by-step explanation:

25% of 60 = 15

10% of 150 = 15

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What is the rate of change
kow [346]
The average rate of change between two input values is the total change of the function values (output values) divided by the change in the input values.
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2 years ago
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How many sixteenth notes would be needed to have the same duration as 3 quarter notes? Represent this as a fraction
Serjik [45]
1 quarter note=2 eighth notes
1 eight note=2 sixteenth notes
so

1 quarter note=4 sixteenth note
so
times 3 both sides
3 quarter notes=12 sixteenth notes
3 0
3 years ago
What is the weight of one half of two thirds of a sack of rice? The sack of rice weighs 99 kilograms.
Eddi Din [679]
First you need to find what 2/3 equals
to do this, take 99 divided by 3
99/3=33

if 1/3 equals 33, two thirds would be 33x2
33x2=66

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1.    66 divided by 2    -    66/2=33
OR
2.    66 x 1/2 = 33     OR     66 x .5 = 33

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6 0
3 years ago
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A recent survey indicated that the average amount spent for breakfast by business managers was $9.33 with a standard deviation o
olasank [31]

Answer:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{9.41-9.33}{\frac{0.24}{\sqrt{81}}}=3    

Step-by-step explanation:

Information given

\bar X=9.41 represent the sample mean

s=0.24 represent the sample standard deviation

n=81 sample size  

\mu_o =9.33 represent the value to verify

\alpha=0.05 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is higher than 9.33, the system of hypothesis would be:  

Null hypothesis:\mu \leq 9.33  

Alternative hypothesis:\mu > 9.33  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{9.41-9.33}{\frac{0.24}{\sqrt{81}}}=3    

4 0
3 years ago
What is the simple interest of a note that has a face value of $12,000, a rate of 8%, and a term of 1 year?
Tju [1.3M]

Solution:

Given:

\begin{gathered} P=\text{ \$}12,000 \\ R=8\text{ \%} \\ T=1year \end{gathered}

Using the simple interest formula,

\begin{gathered} I=\frac{PTR}{100} \\ I=\frac{12000\times1\times8}{100} \\ I=\text{ \$}960 \end{gathered}

Therefore, the simple interest is $960.

8 0
1 year ago
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