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3 years ago

13

Brainliest!!

1 answer:

guajiro [1.7K]3 years ago

7 0

Answer: 100% will have red eyes

Explanation:

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Two scientists do not agree on which type of grocery bag is better for the

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A. They will gather more evidence before reaching a conclusion.

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4 years ago

hichkok12 [17]

An organism that has chloroplasts and vacuoles and moves using a flagellum would be classified as an autotroph.

<h3>What is an autotroph?</h3>

An autotroph is an organism that can generate its own food, which is due to a chemical process called photosynthesis.

Photosynthesis occurs in a specialized organelle called chloroplast that traps sun radiation to convert it into chemical energy.

In conclusion, an organism that has chloroplasts and vacuoles and moves using a flagellum would be classified as an autotroph.

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2 years ago

Which of these is not a principle of natural selection?

BARSIC [14]

Answer: I bleive that it is D Hope it helps

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3 years ago

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Which temperature is required for the cell potential to be the standard cell potential?

Fiesta28 [93]

The answer is B. 25°C.

A temperature of 25°C can be considered as a room temperature. It is an optimal temperature for the most living beings which cell potential is considered as standard. It is known that at 100°C water boils, so this temperature cannot be standard, cells will degrade at this temperature. Similarly 0°C and –273°C are too cold, water of the cells will freeze, cells will freeze, and cell potential will not be optimal.

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4 years ago

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A spheroidal bacterium with a diameter of 1 mm contains 2 molecules of a particular protein. What is the molar concentration?

creativ13 [48]

Answer : The molar concentration is, $6.35\times 10^{-18}mol/L$

Explanation :

First we have to calculate the moles of protein.

$\text{Moles of protein}=\frac{\text{Number of molecules of protein}}{\text{Avogadro's number}}$

Number of molecules of protein = 2 molecules

Avogadro's number = $6.022\times 10^{23}molecules/mol$

$\text{Moles of protein}=\frac{2\text{ molecules}}{6.022\times 10^{23}molecules/mol}=3.32\times 10^{-24}mol$

Now we have to calculate the radius.

Radius = $\frac{Diameter}{2}=\frac{1mm}{2}=0.5mm=5.0\times 10^{-4}m$

Conversion used : (1 mm = 0.001 m)

Now we have to calculate the volume.

$V=\frac{4}{3}\pi r^3$

$V=\frac{4}{3}\times 3.14\times (5.0\times 10^{-4}m)^3$

$V=5.23\times 10^{-10}m^3=5.23\times 10^{-7}L$

Conversion used : (1 m³ = 1000 L)

Now we have to calculate the molar concentration.

$Concentration=\frac{\text{Moles of protein}}{\text{Volume}}$

$Concentration=\frac{3.32\times 10^{-24}mol}{5.23\times 10^{-7}L}$

$Concentration=6.35\times 10^{-18}mol/L$

Thus, the molar concentration is, $6.35\times 10^{-18}mol/L$

4 0

3 years ago