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AlekseyPX
3 years ago
13

..........................

Mathematics
2 answers:
Kay [80]3 years ago
5 0
I think the answer might be a
Olenka [21]3 years ago
3 0

\dfrac{6}{10x^2}\div\dfrac{6}{10x^3+60x^2}=\dfrac{6}{10x^2}\cdot\dfrac{10x^3-60x^2}{6}\\\\=\dfrac{1}{10x^2}\cdot\dfrac{10x^2(x-6)}{1}=x-6\to A.

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The base of the right prism is a rhombus with the side 7 cm. The altitude of the prism is h=13 cm. Find the lateral area of the
Art [367]

Answer:The lateral area is 364\ cm^{2}

Step-by-step explanation:

we know that

The lateral area of the right prism is equal to

LA=Ph

where

P is the perimeter of the base

H is the height of the prism

Find the perimeter of the base P

P=4(7)=28\ cm ----> the rhombus has  four equal sides

h=13\ cm

substitute

LA=28(13)=364\ cm^{2}

6 0
4 years ago
Read 2 more answers
Evaluate the expression when x=4 and y+-6.<br><br> x-5y
rosijanka [135]

Answer:-26

Step-by-step explanation:

4 0
3 years ago
Sela's piano lesson starts at 4:45pm. The lesson is 30 minutes long. When does her lesson end
fredd [130]

Answer:

5:15

Step-by-step explanation:

Split the 30 mins in half. 45+15 = 60 (a new hour) Now, its 5:00. Add 15 and you get the answer.

8 0
3 years ago
HELP help HELP help HELP help HELP help HELP help HELP help HELP help
Morgarella [4.7K]

\text{mass of freight train} = 9.98 \times  {10}^{6} kg

\text{mass of aircraft carrier} = 7.3 \times  {10}^{7}  \: kg

\text{difference of masses of aircraft and train: } \\  \\ 7.3 \times  {10}^{7}  - 9.98 \times  {10}^{6}  \\  \\  = 73 \times  {10}^{6}  - 9.98 \times  {10}^{6}

= (73 - 9.98 )\times  {10}^{6}  \\  \\  = 63.02 \times  {10}^{6}  \\  \\  = 6.302 \times  {10}^{6}  \: kg \\  \\  \approx 6.3 \times  {10}^{6}  \: kg

Approximately, aircraft carrier is 6.3 × 10^6 kg heavier than the freight train.
7 0
3 years ago
Use the Distributive Property to simplify. 8(c - 4) + 3(3c + 7)
Stella [2.4K]

Answer:

=17c−11

Step-by-step explanation:

i hope this helps you

6 0
4 years ago
Read 2 more answers
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