All categories

3 years ago

Consider the Inequalities X >7 and X < 12 select all the values that satisfy both Inequalities

Mathematics

1 answer:

Maksim231197 [3]3 years ago

7 0

Answer:

9;10

Step-by-step explanation:

What we can first do is make them into one double sided inequality and then interpret it from there.

After combining them we get: 7<x<12

This means that any number between 7 and 12 can be picked.

Keep in mind, this means that 7 and 12 cannot be picked, they have to be in between.

Therefore, we get our aswers of 9 and 10!

You might be interested in

The senior classes at High School A and High School B planned separate trips to Lake Compounce. The senior class at High School

storchak [24]

Answer:

Number of students in vans =15 and bus =46

Step-by-step explanation:

use variables for the vans and buses

let x= vans and y=buses

Now solve the 2 equations simultaneously

remember to number your equations

6x+7y=412..........1

6x+9y=504.........2

make x the subject of one equation

and label it equation 3

6x=412—7y

$x = \frac{206}{3} - \frac{7y}{6} .............3$

subs 3 into 2

$6( \frac{206}{3} - \frac{7y}{6} ) + 9y = 504$

$412 - 7y + 9y = 504$

$- 7y + 9y = 504 - 412$

$2y = 92$

$y = 46...................4$

subs 4 into 1

$6x + 7(46) = 412$

$6x + 322 = 412$

$6x = 412 - 322$

$6x = 90$

$x = 15$

Therefore there are 15 students in each van and 46 students in each bus.

3 0

3 years ago

The sum of two numbers is 39. The sum of twice the larger number and three times the smaller number is 93. Find the smaller numb

ExtremeBDS [4]

Answer:3 * (n + 4) = 93

3n + 12 = 93

Subtract 12 to both sides:

3n = 81

Divide 3 to both sides:

n = 27

Step-by-step explanation:

6 0

3 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

4 years ago

[4-2]-10=1 solve the equation

a_sh-v [17]

I think the answer is -20

3 0

3 years ago

Simplify -3x^3(2x^2+3)+9x^4

SIZIF [17.4K]

Answer:

ANSWER = −6x^5 +9x^4 − 9x^3

Step-by-step explanation:

Let's simplify step-by-step.

(−3x^3) (2x^2 + 3) + 9x^4

Distribute:

=(−3x^3) (2x^2) + (−3x^3) (3) + 9x^4

=−6x^5 + − 9x^3 + 9x^4

Answer:

= −6x^5 +9x^4 − 9x^3

3 0

3 years ago