Answer:
34.64
Step-by-step explanation:
<u>Step 1: Round to the nearest hundredth</u>
34.6<u>3</u>52
Since the thousandths place is at or above 5, that means we round up the hundredths place.
34.6<u>3</u>52
34.64
Answer: 34.64
<h3>
Answer: PC = 5</h3>
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Work Shown:
AB+BC+CD = AD .... segment addition postulate
BC+BC+CD = AD ... replace AB with BC (since AB = BC)
BC+BC+BC = AD ... replace CD with BC (since BC = BC)
3*BC = AD .... combine like terms
3*BC = 12 .... replace AD with 12
BC = 12/3 .... divide both sides by 3
BC = 4
For right triangle PBC, the legs are BP = 3 and BC = 4. We can use the Pythagorean Theorem to find that the hypotenuse is PC = 5
The steps are shown below
(BP)^2+(BC)^2 = (PC)^2
3^2+4^2 = (PC)^2
9+16 = (PC)^2
25 = (PC)^2
(PC)^2 = 25
PC = sqrt(25)
PC = 5
The other parts of the diagram seem to be thrown in as a distraction.
Answer:
7
Step-by-step explanation:
To find distance on a number line you add and 2+5=7
Answer:
5 cm
Step-by-step explanation:
We khow that the altitude of this triangle is 1cm shorter than the base
- Let H be our altitude and B our base and A the area of the triangle
- A= (B*H)/2 ⇒ 15=(B*H)/2
- H is 1cm shorter than B ⇒ B=H+1
- H*(H+1)/2=15 ⇒ H*(H+1)=30⇒ H²+H=30⇒H²+H-30+0
that's a quadratic equation . Let's calculate the dicriminant .
Let Δ be the dicriminant
- a=1
- b=1
- c= -30
- Δ=b²-4*a*c = 1²-4*1*(-30)=1+4*30=121≥0
- Δ≥0⇔ that we have two solutions x and y
- x= (-1-)/2= (-1-11)/2= -6
- y= (-1+)/2= 10/2 = 5
We have a negative value and a positive one
The altitude is a distance so it can't be negative
H= 5cm