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yulyashka [42]
1 year ago
11

A retaining wall requires 36.8 cu yd of concrete. The combined amounts of cement, sand, and gavel should be 1 1/2 times the of c

oncrete needed. What total amount of cement, sand, and gavel will be required?
Mathematics
1 answer:
svet-max [94.6K]1 year ago
7 0

Using proportions, it is found that the total amount of cement, sand, and gavel required is of 55.2 cubic yards.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.

The decimal equivalent to the mixed number 1 1/2 is given by:

1 + 1/2 = 1 + 0.5 = 1.5.

1.5 times 36.8 cubic yards is:

1.5 x 36.8 = 55.2.

The total amount of cement, sand, and gavel required is of 55.2 cubic yards.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

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Answer:

The equation which describe this function is 5x + 11y = 37

Step-by-step explanation:

<u>To find the slope</u>

slope = (y₂ - y₁)/(x₂ - x₁)

slope = (13 - 2)/(-2 - 3) = 11/-5

<u>To find the equation</u>

(x - 3)/(y - 2) = -11/5

5(x - 3) = -11(y - 2)

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5x + 11y = 22 + 15

5x + 11y = 37

Therefore the equation which describe this function is

5x + 11y = 37

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3 years ago
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Answer:

\large\boxed{\theta=-\dfrac{\pi}{4}+k\pi\ or\ \theta=k\pi}\ for\ k\in\mathbb{Z}

Step-by-step explanation:

\tan^2\theta+\tan\theta=0\\\\\tan\theta(\tan\theta+1)=0\iff\tan\theta=0\ \vee\ \tan\theta+1=0\\\\\tan\theta=0\Rightarrow \theta=k\pi\ \text{for}\ k\in\mathbb{Z}\\\\\tan\theta+1=0\qquad\text{subtract 1 from both sides}\\\\\tan\theta=-1\Rightarrow\theta=-\dfrac{\pi}{4}+k\pi\ \text{for}\ k\in\mathbb{Z}

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For the equation y=5+6x, what does y equal when x is 4?
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Step-by-step explanation:

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Hoped this helped

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Two classes have a total of 60 students. The students need to make teams of 8t
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