25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer and explanation:
<em>To solve this, you must find what x equals</em>
x + 2x + 7 = 3x - 7 <em>Add together any numbers that can be added on their side</em>
3x + 7 = 3x - 7 <em>Then subtract 7 from both sides to get 3x alone</em>
3x = 3x - 14 <em> Then subtract 3x from both sides to get x</em>
<h3><em>*The x's cancel each other out so you must have typed the equation wrong. Please check to see any mistakes you may have made*</em></h3>
The answer is 7.20 because $18 divided by 2.5% is 7.20
Answer:
There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is 14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is 14!/(23)=10,897,286,400
Answer:
I Think It's 523.6 I don't know Tho
Step-by-step explanation:
