Can you give me the answer ?

Please help what is the answer

Vika [28.1K]

I give a good guess of 42

6 0

3 years ago

PLSS HELP ILL GIVE YOU A BRAINLIEST AND 30 points!

jekas [21]

A :-) 1.) Given - base = 9 cm
height ( alt ) = 12 cm
hypotenuse ( hypo ) = x
Solution -
By Pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 9 )^2 + ( 12 ) ^2
( x )^2 = 81 + 144
( x )^2 = 225
( x ) = _/225
( x ) = 15 cm

.:. The value of x ( hypotenuse ) = 15 cm

2.) Given - base = 10 cm
Height = 24 cm
Hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 10 )^2 + ( 24 )^2
( x )^2 = 100 + 576
( x )^2 = 676
( x ) = _/676
( x ) = 26

.:. The value of x ( hypotenuse ) = 26 cm

3.) Given - base = 3 cm
Height = 7 cm
Hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 3 )^2 + ( 7 )^2
( x )^2 = 9 + 49
( x )^2 = 58
( x ) = _/58
( x ) = 7.6

.:. The value of x ( hypotenuse ) = 7.6 cm

4.) Given - base = 10 cm
Height = 6 cm
Hypotenuse = x
Solution -
By pythagorus theorem
( Hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 10 )^2 + ( 6 )^2
( x )^2 = 100 + 36
( x )^2 = 136
( x ) = _/136
( x ) = 11.6

.:. The value of x ( hypotenuse ) = 11.6 cm

5.) Given - hypotenuse = 24 cm
height = 6 cm
Base = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( 24 )^2 = ( x )^2 + ( 6 )^2
( x )^2 = ( 6 )^2 - ( 24 )^2
( x )^2 = 36 - 576
( x )^2 = -540
( x ) = _/-540
( x ) = 23.2

.:. The value of x ( base ) = 23.2 cm

6.) Given - base = 1 cm
height = 1 cm
hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 1 )^2 + ( 1 )^2
( x )^2 = 1 + 1
( x )^2 = 2
( x ) = _/2
( x ) = 1.4

.:. The value of x ( hypotenuse ) = 1.4 cm

7.) Given - hypotenuse = 21 cm
height = 8 cm
Base = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( 21 )^2 = ( x )^2 + ( 8 )^2
441 = ( x )^2 + 64
( x )^2 = 64 - 441
( x )^2 = -377
( x ) = _/-377
( x ) = 19.4

.:. The value of x ( base ) = 19.4

8.) given - height = 24 cm
Hypotenuse = 30cm
Base = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( 30 )^2 = ( x )^2 + ( 24 )^2
900 = ( x )^2 + 576
( x )^2 = 576 - 900
( x )^2 = -324
( x ) = _/-324
( x ) = 18

.:. The value of x ( base ) = 18 cm

9.) ( i ) lets find ‘x’
Given - base = 9 cm
height = 5 cm
hypotenuse = x
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( x )^2 = ( 9 )^2 + ( 5 )^2
( x )^2 = 81 +25
( x )^2 = 106
( x ) = _/106
( x ) = 10.2

.:. The value of x ( hypotenuse )
= 10.2 cm

( ii ) lets find ‘y’
Given - base = 3 cm
height = 5 cm
Hypotenuse = y
Solution -
By pythagorus theorem
( hypo )^2 = ( base )^2 + ( alt )^2
( y )^2 = ( 3 )^2 + ( 5 )^2
( y )^2 = 9 + 25
( y )^2 = 34
( y ) = _/34
( y ) = 5.8

.:. The value of y ( hypotenuse )
= 5.8 cm

4 0

3 years ago

Im being timed! HURRYYYYYYYYY simplify:

Mamont248 [21]

Answer:

B. $p^2+p-11$ .

Step-by-step explanation:

Step 1:

$((((3+(4*(p^2)))-5p)-3p^2)+4p)+8$

Step 2:

$((((3 + 22p^2) - 5p) - 3p^2) + 4p) + 8$

Step 3:

Factoring $p^2-p+11$
The first term is, $p^2$ its coefficient is 1 .
The middle term is, -p its coefficient is -1 .
The last term, "the constant", is +11
Step-1 : Multiply the coefficient of the first term by the constant 1 • 11 = 11
Step-2 : Find two factors of 11 whose sum equals the coefficient of the middle term, which is -1 .
-11 + -1 = -12
-1 + -11 = -12
1 + 11 = 12
11 + 1 = 12
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored