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miss Akunina [59]
3 years ago
6

Please help with this math problem for trig. A 6 m ladder is leaning against a wall. The base of the ladder is 1.5 m from the wa

ll. Calculate how high up the wall the ladder reaches.
Mathematics
1 answer:
VladimirAG [237]3 years ago
4 0

Answer:

a = 5.81 m

Step-by-step explanation:

We can use the Pythagorean theorem

a^2 + b^2 = c^2

where b= 1.5 and c= 6

a^2 +1.5^2 = 6^2

a^2 +2.25 = 36

Subtract 2.25 from each side

a^2 +2.25-2.25 = 36-2.25

a^2 = 33.75

Take the square root of each side

sqrt(a^2) = sqrt(33.75)

a = 5.809475019

We only take the positive root because length must be positive

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8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

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Step-by-step explanation:

cos 45° = distance to east / total distance=7,2

distance to east = cos 45° * 7,2 = 5,1 km

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2 years ago
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