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Doss [256]
3 years ago
14

The two-way relative frequency table shows the relative frequencies of late night workers and day workers who do or do not drink

coffee. What percent of late night workers do not drink coffee?
Work late night jobs Work day jobs
Drink coffee 0.733 0.455
Don’t drink coffee 0.267 0.545

The answer has to be in percent please help.
Mathematics
2 answers:
MatroZZZ [7]3 years ago
5 0
26.7 is your answer i hope that helps 

zmey [24]3 years ago
5 0

Answer:

26.7 % of late night workers don't drink coffee.

Step-by-step explanation:

Let's write the data from the two - way relative frequency table :

Workers late night jobs that drink coffee = 0.733

Workers late night jobs that don't drink coffee = 0.267

Workers day jobs that drink coffee = 0.455

Workers day jobs that don't drink coffee = 0.545

If we want to find the percent of late night workers that don't drink coffee we need to look at the part of the table that has the information about late night workers.

On that side of the frequency table, we can see that the relative frequency of late night workers that don't drink coffee is 0.267

This relative frequency means that for example, in a sample of 1000 late night workers :

(1000).(0.267)=267

Approximately 267 of late night workers in the sample of 1000 don't drink coffee.

If we want to express this result using percent we need to multiply the relative frequency by 100 ⇒

(0.267).100=26.7

Approximately  26.7 % of the late night workers don't drink coffee.

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Let f (x) = 3x − 1 and ε > 0. Find a δ > 0 such that 0 < ∣x − 5∣ < δ implies ∣f (x) − 14∣ < ε. (Find the largest
s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and \varepsilon>0, we want to find a \delta such that |f(x)-14|

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that |x-5|. Then

|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta.

Then, if |x-5|, then |f(x)-14|. So, in this case, if 3\delta \leq \varepsilon we get that |f(x)-14|. The maximum value of delta is \frac{\varepsilon}{3}.

By definition, this procedure proves that \lim_{x\to 5}f(x) = 14. Note that f(5)=14, so this proves that f is continous at x=5.

3 0
3 years ago
PLEASE ANSWER THIS ASAP !!!!
AveGali [126]

Answer:

use grad formula

Step-by-step explanation:

(4-10)/(46-31)=-2/5

8 0
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How do I rotate a figure 90 degrees clockwise
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Step-by-step explanation:

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5 0
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Hope this helps!!!!
7 0
3 years ago
Read 2 more answers
URGENT: the question is in the attachment below
joja [24]

Simultaneous equation refer to a pair of equations that are solved at the same time.

<h3>What is a simultaneous equation?</h3>

A  simultaneous equation refer to a pair of equations that are solved at the same time.

For problem 1;

x = 4 - y ------ (1)

y^2 = 3x + 19 ----- (2)

Substitute (1) into (2)

y^2 = 3(4 - y) + 19

y^2 = 12 - 3y + 19

y^2 +3y - 31 =0

y = 4.27 or -7.27

x = 4 - 4.27 = 0.27

or

x = 4 - (-7.27) = 11.27

For the second problem;

x = 7 - y

y^2 = 5x - 15

Substitute (1) into (2)

y^2 = 5(7 - y) - 15

y^2 =35 -5y -15

y^2 + 5y - 20 = 0

y =2.62 or -7.62

x = 7 - 2.62 = 4.38

OR

x=  7 - (-7.62) = 14.62

Learn more about simultaneous equation:brainly.com/question/16763389

#SPJ1

8 0
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