)Allison has a poster that is 15 in by 18 in. What will the dimensions of the poster be if she scales it down by a factor of one
-third ? A. 15 in by 18 in B.45 in by 54 in C.2.5 in by 2 in D.5 in by 6 in
2 answers:
The answer will be D: 5 inches by 6 inches because both of the dimensions are divided by three.
15 x 18
multiply each by 1/3
5 x 6
<span>D. 5 in by 6 in</span>
You might be interested in
complementary angles add up to 90°, so therefore we know that ∡A + ∡B = 90°, and also they are in a ratio of 3:6.
![\bf \cfrac{A}{B}=\cfrac{3}{6}\implies \cfrac{A}{B}=\cfrac{1}{2}\implies 2A=\boxed{B} \\\\[-0.35em] ~\dotfill\\\\ A+B=90\implies A+\boxed{2A}=90\implies 3A=90\\\\\\ A=\cfrac{90}{3}\implies \blacktriangleright A=30 \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 2(30)=B\implies \blacktriangleright 60=B \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7BA%7D%7BB%7D%3D%5Ccfrac%7B3%7D%7B6%7D%5Cimplies%20%5Ccfrac%7BA%7D%7BB%7D%3D%5Ccfrac%7B1%7D%7B2%7D%5Cimplies%202A%3D%5Cboxed%7BB%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%5C%5C%5C%5C%0AA%2BB%3D90%5Cimplies%20A%2B%5Cboxed%7B2A%7D%3D90%5Cimplies%203A%3D90%5C%5C%5C%5C%5C%5C%20A%3D%5Ccfrac%7B90%7D%7B3%7D%5Cimplies%20%5Cblacktriangleright%20A%3D30%20%5Cblacktriangleleft%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A2%2830%29%3DB%5Cimplies%20%5Cblacktriangleright%2060%3DB%20%5Cblacktriangleleft)
The avarage is 180:18=10 , 10 min per hole
y = 2(x - 1)² + 4
y = 2(x² - 2x + 1) + 4
y = 2x² - 4x + 2 + 4
y = 2x² - 4x + 6
Step-by-step explanation:
2:3:5
2+3+5=10
2÷10 ×72=$14.4
3÷10×72=$21.6
5÷10×72=$36
Answer:
240 If its wrong pleas correct me