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artcher [175]
3 years ago
8

)Allison has a poster that is 15 in by 18 in. What will the dimensions of the poster be if she scales it down by a factor of one

-third ? A. 15 in by 18 in B.45 in by 54 in C.2.5 in by 2 in D.5 in by 6 in
Mathematics
2 answers:
luda_lava [24]3 years ago
6 0
The answer will be D:  5 inches by 6 inches because both of the dimensions are divided by three.
Sholpan [36]3 years ago
6 0
15 x 18
multiply each by 1/3
5 x 6

<span>D. 5 in by 6 in</span>
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Do you want us to simplify? If so, it would be 3/5


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Pls help ASAP!!! will do brainliest
amm1812

Answer:

1a

2b

3a

4c

5c

6c

7a

8d

9b

10b

11a

12c

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15a

Step-by-step explanation:

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3 years ago
What decimal fraction is between 1.2 and 1.5
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1.2=1\frac{2}{10}=1\frac{2:2}{10:2}=1\frac{1}{5}\\\\1.5=1\frac{5}{10}=1\frac{5:5}{10:5}=1\frac{1}{2}\\\\1\frac{1}{5} < \boxed{1\frac{1}{4} < 1\frac{1}{3}}
7 0
3 years ago
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In a sample of 679 new websites registered on the Internet, 42 were anonymous (i.e., they shielded their name and contact inform
Semmy [17]

Answer:

95% Confidence interval:  (0.0429,0.0791)      

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 679

Number of anonymous websites, x = 42

\hat{p} = \dfrac{x}{n} = \dfrac{42}{679} = 0.0618

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

Putting the values, we get:

0.0618\pm 1.96(\sqrt{\dfrac{0.0618(1-0.0618)}{679}}) = 0.0618\pm 0.0181\\\\=(0.0429,0.0791)

is the required confidence interval for proportion of all new websites that were anonymous.

8 0
3 years ago
Ethan is responsible to write the minutes for the meeting. During the meeting, he finished writing of the minutes. Before gettin
dolphi86 [110]
11/24
1. 3/8 = 9/24
2. 1/6 = 4/24
3. 9/24 + 4/24 = 13/24
4. 1- 13/24 = 11/24

And that’s if! Hoped this helped :)
These are all the correct steps to get the answer to this problem
7 0
3 years ago
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