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Temka [501]
2 years ago
7

The quotient of a number and 0.004 is 60. Find the number​

Mathematics
1 answer:
tatuchka [14]2 years ago
7 0

Answer:

Step-by-step explanation:

x/.004 = 60

solve x

x = .24

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Someone please help ASAP will give brainliest
Svetach [21]

Answer:

A

Step-by-step explanation:

The degree is cubic (3) and there are 3 terms X^3, X^2, X

7 0
2 years ago
Find the quotient. (2x^4-3x^3-6x^2+11x+8)/(x-2)
stiv31 [10]

Since the remander is 0 the answer is 2x²+5x+2

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2 years ago
Read 2 more answers
Evaluate the expression using a calculator:
tester [92]

The value of the expression is 0.0265. Using exponents and power rules, the required value is calculated.

<h3>What are the exponent and power rules?</h3>

The important exponent and power rules are:

  • a⁻ⁿ = 1/aⁿ; negative exponent
  • (ab)ⁿ = aⁿ × bⁿ; power of a product rule
  • aⁿ × aˣ = aⁿ⁺ˣ; multiplication rule
  • aⁿ/aˣ = aⁿ⁻ˣ; division rule
  • a^{\frac{x}{y} } = \sqrt[y]{a^x}; fractional exponent

<h3>Calculation:</h3>

The given expression is 126^{-3/4}

Using calculator: 126^{-3/4} = 0.0265

Applying the exponent rule for evaluating the given expression:

126^{-3/4}

Applying the negative power rule;

I.e., a⁻ⁿ = 1/aⁿ

⇒ 126^{-3/4}=\frac{1}{126^{3/4}}

Applying fractional exponent rule;

I.e., a^{\frac{x}{y} } = \sqrt[y]{a^x}

⇒ \frac{1}{126^{3/4}}=\frac{1}{\sqrt[4]{126^3} }

⇒ 1/\sqrt[4]{2000376}

⇒ 1/37.6077

⇒ 0.0265

Therefore, the value of the given expression is 0.0265.

Learn more about exponent rules here:

brainly.com/question/11975096

#SPJ1

4 0
8 months ago
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coldgirl [10]

Answer:

The second one

Step-by-step explanation:

7 0
3 years ago
Rewrite (2x^2+13x+26) / x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x). In the rewritten expression, q(x) is_____and r
likoan [24]

The value of q(x) is 2 x+5

The value of r(x) is 6

Explanation:

The given expression is \frac{2 x^{2}+13 x+26}{x+4}

We need to rewrite the expression in the form of q(x)+\frac{r(x)}{b(x)}

Simplifying the expression, we get,

\frac{2 x^{2}+8 x+5x+26}{x+4}

Separating the fractions, we have,

\frac{2 x^{2}+8 x}{x+4}+\frac{5 x+26}{x+4}

2 x+\frac{5 x+26}{x+4}  -----------(1)

Now, we shall further simplify the term \frac{5 x+26}{x+4} , we get,

\frac{5 x+26}{x+4}=\frac{5 x+20}{x+4}+\frac{6}{x+4}

Common out 5 from the numerator, we have,

\frac{5 x+26}{x+4}=5+\frac{6}{x+4}

Substituting the value \frac{5 x+26}{x+4}=5+\frac{6}{x+4} in the equation(1), we get,

2 x+5+\frac{6}{x+1}

Thus, the expression \frac{2 x^{2}+13 x+26}{x+4}=2 x+5+\frac{6}{x+1} is in the form of q(x)+\frac{r(x)}{b(x)}

Hence, we have,

q(x)=2 x+5

r(x)=6 and

b(x)=x+4

5 0
3 years ago
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