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3 years ago

What does a car's design have to do with science?

Mathematics

2 answers:

Kobotan [32]3 years ago

6 0

Answer:

A car's design can affect its aerodynamical performance.

Step-by-step explanation:

alexgriva [62]3 years ago

3 0

Answer:

How it drives and the resistance to the wind and other elements of the outdoors

Step-by-step explanation:

You might be interested in

The annual rainfall (in inches) in a certain region is normally distributed with mean 43.2 and variance 20.8. Assume rainfall in

Wittaler [7]

Answer:

92.24% probability that out of 15 years, at most 2 have rainfall of more than 50 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the binomial probability distribution.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation(which is the square root of the variance) $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

$\mu = 43.2, \sigma = \sqrt{20.8} = 4.56$

Probability that a year has rainfall of more than 50 inches.

pvalue of Z when X = 50. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{50 - 43.2}{4.56}$

$Z = 1.49$

$Z = 1.49$ has a pvalue of 0.9319

1 - 0.9319 = 0.0681

Find the probability that out of 15 years, at most 2 have rainfall of more than 50 inches.

This is $P(X \leq 2)$ when $n = 15, p = 0.0681$ . So

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{15,0}.(0.0681)^{0}.(0.9319)^{15} = 0.3472$

$P(X = 1) = C_{15,1}.(0.0681)^{1}.(0.9319)^{14} = 0.3805$

$P(X = 2) = C_{15,2}.(0.0681)^{2}.(0.9319)^{13} = 0.1947$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.3472 + 0.3805 + 0.1947 = 0.9224$

92.24% probability that out of 15 years, at most 2 have rainfall of more than 50 inches.

8 0

3 years ago

Read 2 more answers

Randolph is creating rectangle WXYZ so that WX has an equation of y = 1 over 4x + 4. Segment XY must pass through the point (−2,

Sliva [168]

Answer:

The correct option is;

c.) y - 6 = -4(x - (-2))

Step-by-step explanation:

We note that the figure Randolph is creating is a rectangle, therefore, we have;

$\overline{WX}\perp \overline{XY}$ , therefore, we have;

$\overline{WX} = \dfrac{1}{4} x + 4$

∴ Slope $\overline{WX}$ = 1/4

$\overline{XY}$ must pas through the point (-2, 6)

Given that $\overline{WX}\perp \overline{XY}$ , we have;

$Slope \ \overline{XY} = \dfrac{-1}{Slope \ \overline{WX}}$

$\dfrac{y - 6}{x - (-2)} = -1/\dfrac{1}{4} = -4$

y - 6 = -4(x - (-2))

Therefore, the correct option is c.) y - 6 = -4(x - (-2)).

6 0

3 years ago

If two variables were completely correlated, their correlation coefficient would be:

meriva

<span>Pearson's correlation coefficient 'r' measures the degree to which two variables are correlated. The value is between -1 and 1. Negative values correspond to negative correlation (as one variable increases, the other variable decreases) whereas positive values correspond to positive correlation. The larger the absolute value of r, the closer a correlation graph resembles a set of points on the same line. Therefore, if two variables are completely correlated, the correlation value is 1 or -1, depending on whether the correlation is positive or negative.</span>

7 0

3 years ago

I need help asap !!!!!!

OLEGan [10]

Answer:

B. ZJ = 85

C. KH = 68

Step-by-step explanation:

Given that ZK, ZL, ZM are perpendicular bisectors of ∆GHJ, they form a circumcenter which is equidistant from the vertices of ∆GHJ. According to the circumcenter theorem, ZH = ZG = ZJ = 85.

Also each median formed is equal. This means: KH = GH, LH = LJ, MG = MJ

Since HG = 136, KH = ½ of 136 = 68.

The two options that are true are:

B. ZJ = 85

C. KH = 68

4 0

3 years ago

Locate and plot √11 on a number line. Find a better approximation using decimals. 3.2×3.2= 3.4×3.4 = (Type integers or decimals.

ki77a [65]

Answer:

The point 'R' shows the irrational number √11 on the given number line and for better proximation using decimals, 3.2×3.2= 10.24; 3.4×3.4= 11.56

Step-by-step explanation:

It is given that we have to locate √11 on a number line, so for that we need to mark point 'O' on the number line as shown;

Now,

On the number line, point 'O' represent 0 and the point 'L' represents 3. Thus, we have OL = 3 units.

Now, we will construct LM = 1 unit, which will be perpendicular to the number line given;

=> OM = √10

Now, we will further construct MN = 1 unit, which will be perpendicular to OM;

=> ON² = OM² + MN²

=> ON = √OM² + MN²

=> √(10)² + (1)²

=> √10+1

=> √11

Furthermore, With O as the center and ON = √11 for the radius, we create an arc that crosses the number line at R resulting that line OR = √11 (radius).

Therefore, the point 'R' shows the irrational number √11 on the given number line.

For better proximation using decimals, the answers are:

3.2 × 3.2 = 10.24

3.4 × 3.4 = 11.56

<u>To know more about representation on number line, click here</u>:

brainly.com/question/13425491

#SPJ10

8 0

2 years ago