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ICE Princess25 [194]
4 years ago
12

What is the simplified expression for 4 to the -3rd power times 3 to the 4th power times 4 to the 2nd power over 3 tothe 5th pow

er times 4 to the -2nd power?
Mathematics
1 answer:
Cloud [144]4 years ago
5 0

Answer:

21.33333333333333333

Step-by-step explanation:

You might be interested in
Where is the point -3,4 located on a coordinate plane?
tatyana61 [14]

Answer:

It is located 3 to the right and 4 up or in the second quadrant

Step-by-step explanation:

8 0
3 years ago
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Three different members of the set {4,5,6,7,8,9} are chosen at random and added. How many different sums are possible?
Aloiza [94]

Answer:

10

Step-by-step explanation:

4+5+6=15,

4+5+7=16,

4+5+8=17,

4+5+9=18,

4+6+7=17,

4+6+8=18,

4+6+9=19,

4+7+8=19,

4+7+9=20,

4+8+9=21,

5+6+7=18,

5+6+8=19,

5+6+9=20,

5+7+8=20,

5+7+9=21,

5+8+9=22,

6+7+8=21,

6+7+9=22,

6+8+9=23,

7+8+9=24.

There are sums 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 10 different sums in total.

6 0
3 years ago
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Can some one help me find the 5 coordinates that's it. And I'll plug them into my equation thanks c:
avanturin [10]
(0,0), (-4,-2), (-4,3), (-9,-3), (-9,3)
7 0
3 years ago
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A certain type of thread is manufactured with a mean tensile strength of 78.3 kilograms and a standard deviation of 5.6 kilogram
azamat

Answer:

(a) The variance decreases.

(b) The variance increases.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Then, the mean of the sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The standard deviation of sample mean is inversely proportional to the sample size, <em>n</em>.

So, if <em>n</em> increases then the standard deviation will decrease and vice-versa.

(a)

The sample size is increased from 64 to 196.

As mentioned above, if the sample size is increased then the standard deviation will decrease.

So, on increasing the value of <em>n</em> from 64 to 196, the standard deviation of the sample mean will decrease.

The standard deviation of the sample mean for <em>n</em> = 64 is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{64}}=0.7

The standard deviation of the sample mean for <em>n</em> = 196 is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{196}}=0.4

The standard deviation of the sample mean decreased from 0.7 to 0.4 when <em>n</em> is increased from 64 to 196.

Hence, the variance also decreases.

(b)

If the sample size is decreased then the standard deviation will increase.

So, on decreasing the value of <em>n</em> from 784 to 49, the standard deviation of the sample mean will increase.

The standard deviation of the sample mean for <em>n</em> = 784 is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{784}}=0.2

The standard deviation of the sample mean for <em>n</em> = 49 is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5.6}{\sqrt{49}}=0.8

The standard deviation of the sample mean increased from 0.2 to 0.8 when <em>n</em> is decreased from 784 to 49.

Hence, the variance also increases.

6 0
3 years ago
last question on the page answer correctly or don't answer at all please because this is an annoying question
Dvinal [7]
Ii can’t see the pic?
5 0
3 years ago
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