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siniylev [52]
3 years ago
10

A diagonal of a cube measures the square root of 150 cm. The diagonal of a face measures 10 cm. What is the length, in centimete

rs, of an edge of the cube? Round the answer to the nearest tenth.

Mathematics
2 answers:
Makovka662 [10]3 years ago
6 0
This problem is just one about triangles! All of the faces of the cube are perpendicular to their adjacent faces, so the diagonal of one of the face will be a right angle with the edge of the cube. Thus, you can create a right triangle. Finally, use the Pythagorean Theorem to solve for x, the length of the side of the cube. You should get that the edge has a length of the square root of 50 centimeters, or 7.1 centimeters when rounded to the nearest tenth. Hope this helps!

faltersainse [42]3 years ago
6 0

Answer:

The edge of the cube is 7.07 cm or 5√2 cm

Step-by-step explanation:

Given : A diagonal of a cube measures the square root of 150 cm.

           The diagonal of a face measures 10 cm.

To Find: What is the length, in centimeters, of an edge of the cube?

Solution:

Since the face of the cube is in the shape of square .

The diagonal of that face is 10 cm.

Since the formula of diagonal of square = \sqrt{2} a

Where a is the side of square face

So, \sqrt{2} a=10

a=\frac{10}{\sqrt{2}}

a=\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}

a=\frac{10\sqrt{2}}{2}

a=5\sqrt{2}

a=7.07 cm

Since the side of the square face is the edge of the cube

Hence the edge of the cube is 7.07 cm or 5√2 cm

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3 0
4 years ago
What is f(x) = 7x2 42x written in vertex form? f(x) = 7(x 6)2 – 6 f(x) = 7(x 6)2 – 42 f(x) = 7(x 3)2 – 9 f(x) = 7(x 3)2 – 63.
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The vertex form of the function f(x) is \rm f(x)= 7 ( x + 3 )^2 - 63.

<h2>Given </h2>

Function; \rm f(x) = 7x^2 + 42x

<h3>What is the vertex form of function?</h3>

The vertex of a parabola is the point at which the parabola passes through its axis of symmetry.

The standard equation which represents the vertex form of the function is;

\rm f(x) =(x-h)^2+k^2

Where h and k are vertexes of the given parabola.

The function is in vertex form;

\rm f(x)= 7 x^2 + 42 x\\\\ f(x) = 7 ( x^2+ 6 x ) \\\\ f(x)= 7 ( ( x^2+ 6 x + 9 ) - 9 ) \\\\ f(x)= 7 ( x + 3 )^2 - 63

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To know more about the Vertex form lick the link given below.

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