Rewrite 4x^2-3x+9=2x+1 as 4x^2-5x+8 = 0
Here, a = 4, b = -5 and c = 8. Then,
5 plus or minus sqrt (25 -4(4)(8) )
x = ------------------------------------------------------
8
5 plus or minus sqrt (-103)
= --------------------------------------
8
5 plus or minus i*sqrt(103)
Then x = ----------------------------------------
8
= ---------------------------------------------
8
= ----------------------------
It would be 4/134, and simplified that is 2/67.
So it would be 2 teachers to 67 students
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Find Radius :
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Radius of the semicircle = 10 ÷ 2 = 5cm
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Find Area of the semi circle :
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Area of the semi circle = 1/2 πr²
Area of the semi circle = 1/2 x π x (5)²
Area of the semi circle = 12.5π cm²
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Find Radius :
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Radius of the inner circle = 5 ÷ 2 = 2.5 cm
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Find area of inner circle :
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Area of the inner circle = πr²
Area of the inner circle = π x (2.5)²
Area of the inner circle = 6.25π
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Area of the shaded region :
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Area of the shaded region = 12.5π - 6.25π
Area of the shaded region = 6.25π
Area of the shaded region = 19.63 cm²
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Answer: Area of the shaded region = 19.63 cm²
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Answer:
b
Step-by-step explanation:
not sure but i think thats the answer since 36.9/30 =1.23
Answer: =
−
5
+
√
48
y
2
+
180
y
+
25
6
y
x
=
-
5
+
48
y
2
+
180
y
+
25
6
y
x
=
−
5
−
√
48
y
2
+
180
y
+
25
6
y
Step-by-step explanation:
Hope this helps!