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Zarrin [17]
3 years ago
8

Find the properties of each Quadratic Function

Mathematics
1 answer:
Alla [95]3 years ago
7 0

Answer:

1.) up

2.) (-2,-5)

3.) x = -2

4.) (-2,-5)

5.) y = -5

6.) -∞ < x < ∞

7.) -5 < y < ∞

8.) (0,0)

9.) (0,0) and (-4,0)

10.) two solutions

Step-by-step explanation:

1.) because the parabola opens upward and the vertex is down

2.) the lowest point of the parabola is (-2,-5)

3.) If a line was drawn through the point x = -2, the two halves of the parabola would look symmetrical ( the same on both sides).

4.) The minimum point on the graph is ( -2,-5), because that is the lowest point on this upward parabola, and we can not determine the maximum.

5.) The minimum value of y is y = -5, because that is the lowest value of y on this graph, and we can not determine the maximum.

6.) Because the arms of the parabola continue traveling through negative infinity and positive infinity on the x-axis, the domain is -∞ < x < ∞.

7.) The arms of the parabola go from y = -5 to infinity, so the range of the parabola is -5 < y < ∞.

8.) The parabola first crosses the y-axis at the point (0,0)

9.) The parabola first crosses the x-axis at the points (0,0) and (-4,0)

10,) The solution to the parabola is the variable x. The solutions (x intercepts) of the parabola are x = 0 and x = -4.

Does this help you?

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Less

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Hope this answer helped!
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4 years ago
Mia's Cafe has regular coffee and decaffeinated coffee. This morning, the cafe served 25 coffees in all, 15 of which were regula
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4 years ago
A manager asked her employees how many times they had given blood in the last year. The results of the survey are given below. T
stira [4]

<u>Complete Question</u>

The probability distribution table is given below:

\left|\begin{array}{c|ccccccc}x&0&1&2&3&4&5&6\\P(x) &0.33 &0.24& 0.16& 0.12 &0.08 &0.05& 0.02\end{array}\right|

Answer:

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Step-by-step explanation:

The probability distribution table is given below:

\left|\begin{array}{c|ccccccc}x&0&1&2&3&4&5&6\\P(x) &0.33 &0.24& 0.16& 0.12 &0.08 &0.05& 0.02\end{array}\right|

We want to determine the mean number of times a person gave blood.

Expected Value, E(x)=\sum x_i\cdot P(x_i)

=(0 \times 0.33)+ (1 \times 0.24)+(2\times0.16)+(3\times0.12)+(4\times0.08)+(5\times0.05)+(6\times0.02)\\=0+0.24+0.32+0.36+0.32+0.25+0.12\\=1.61\\

The mean number of times a person gave blood based on this survey is 1.61.

4 0
4 years ago
Y = 2x + 1<br> y = 4x - 1
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Answer:

1

Step-by-step explanation:

Y = 2X +1

= 2(0)+1

=0 + 1

=1

7 0
4 years ago
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