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Mila [183]
4 years ago
13

Use the Venn diagram to calculate probabilities.

Mathematics
2 answers:
sergejj [24]4 years ago
6 0
1. The number of elements of the universal set, or the sample space is 59

2. P(A|C) is the probability of A to happen once we know C has occured

it is calculated using the formula P(A|C) = P(A <span>∩ C</span>) / P(C) = (14/59)/(21/59)=14/21=2/3

3. P(C|B) = P(C ∩ B) / P(B) = (11/59)/(27/59)=11/27

4. P(C)=(6+8+3+4)/59=21/59

5. P(B|A) = P(B ∩ A) / P(A) = (13/59)/(31/59)=13/31

Correct answer: <span>P(A|C) = 2/3</span>
Vlad [161]4 years ago
5 0

Total number of elements in the set =59.

1)P(A|C) = P(A ∩ C) / P(C)  = \frac{14}{21}=\frac{2}{3}

2)P(C|B) = P(C ∩ B) / P(B) =\frac{11}{27}

3) P(A) =\frac{31}{59}.

4)P(C) =\frac{21}{59}.

5)P(B|A)=P(B ∩ A) / P(A)=\frac{13}{31}

Options 1 and 3  are right.

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Please help!
BaLLatris [955]

a) The polynomial in expanded form is f(x) = x^{3}-2\cdot x^{2}-21\cdot x -18.

b) The slant asymptote is represented by the linear function is y = -x + 1.

c) There is a discontinuity at x = 2  with a slant asymptote.

a) In this question we are going to use the Factor Theorem, which establishes that polynomial are the result of products of binomials of the form x-r_{i}, where r_{i} is the i-th root of the polynomial and the grade is equal to the quantity of roots. Therefore, the polynomial f(x) has the following form:

f(x) = (x-6)\cdot (x+1)\cdot (x+3)

And the expanded form is obtained by some algebraic handling:

f(x) = (x-6)\cdot (x^{2}+4\cdot x +3)

f(x) = x\cdot (x^{2}+4\cdot x + 3)-6\cdot (x^{2}+4\cdot x +3)

f(x) = x^{3}+4\cdot x^{2}+3\cdot x -6\cdot x^{2}-24\cdot x -18

f(x) = x^{3}-2\cdot x^{2}-21\cdot x -18 (1)

The polynomial in expanded form is f(x) = x^{3}-2\cdot x^{2}-21\cdot x -18.

b) In this question we divide the polynomial found in a) (in factor form) by the polynomial x^{2}-x -2 (also in factor form). That is:

g(x) = \frac{(x-6)\cdot (x+1)\cdot (x+3)}{(x-2)\cdot (x+1)}

g(x) = \frac{(x-6)\cdot (x+3)}{x-2} (2)

The slant asymptote is defined by linear function, whose slope (m) and intercept (b) are determined by the following expressions:

m =  \lim_{x \to \pm \infty} \frac{g(x)}{x} (3)

b =  \lim_{x \to \pm \infty} [g(x)-x] (4)

If g(x) = \frac{(x-6)\cdot (x+3)}{x-2}, then the equation of the slant asymptote is:

m =  \lim_{x \to 2} \frac{(x-6)\cdot (x+3)}{x\cdot (x-2)}

m =  \lim_{x \to \pm \infty} \left(\frac{x^{2}-3\cdot x -18}{x^{2}-2\cdot x} \right)

m =  1

b =  \lim_{x \to \pm \infty} \left(\frac{x^{2}-3\cdot x -18}{x-2}-x \right)

b =  \lim_{x \to \pm \infty} \left(\frac{x^{2}-3\cdot x - 18-x^{2}+2\cdot x}{x-2}\right)

b =  \lim_{n \to \infty} \left(\frac{-x-18}{x-2} \right)

b = -1

The slant asymptote is represented by the linear function is y = -x + 1.

c) The number of discontinuities in rational functions is equal to the number of binomials in the denominator, which was determined in b). Hence, we have a discontinuity at x = 2  with a slant asymptote.

We kindly invite to check this question on asymptotes: brainly.com/question/4084552

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Answer:

4a2−b2−2a+b, there are no factorable rational numbers.

Step-by-step explanation:

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Answer:

y-2=5/3x

y-2/5=3x

Step-by-step explanation:

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