Kenny weight is 6/7 times Melvin weight. What is the ratio of Kenny weight to Melvin weight? Give answer in fraction form

Mathematics

1 answer:

Firlakuza [10]3 years ago

4 0

Let's call Kenny's weight K, Melvin's weight M.
We know that K=6/7*M hence K/M=6/7

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$f(x) = \frac{1}{6}(x^3 -10x^2+31x-30)$

For finding y - intercept we simply plugin x = 0 in given equation.
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