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mihalych1998 [28]
2 years ago
5

Find the formula for the nth term of the arithmetic sequence a1=15,d=9​

Mathematics
1 answer:
sasho [114]2 years ago
8 0
The answer to this is a n = a1 + d(n - 1)
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What value of x will make triangles ABM and DCM<br> congruent?<br> 3<br> 5<br> 7<br> 9
kykrilka [37]
The congruent side is going to be 9
6 0
2 years ago
Complete the table<br> Original Price:?<br> Percent of Discount: 25%<br> Sale Price: $40
BigorU [14]

Answer:

<u><em>The original price would be 50$.</em></u>

Step-by-step explanation:

To find this answer you have to divide 25% by 100, which equals 0.25.  Now multiply 0.25 by 40 and you get 10$.  Since 10$ was the discount, you just add 10$ + 40$, therefore 50$ is the original price.

8 0
3 years ago
What is the true solution In 20+In 5=2 In x?
S_A_V [24]

Answer:

x = 10

Step-by-step explanation:

Using the rules of logarithms

• log x + log y ⇔ log(xy)

• logx^{n} ⇔ n log x

• log x = log y ⇒ x = y

Given

ln20 + ln5 = 2 lnx , then

ln(20 × 5) = lnx^{2}

ln 100 = lnx^{2}, hence

x² = 100 ( take the square root of both sides )

x = 10

7 0
3 years ago
Find the inverse of ????−7 −2
Masja [62]

Answer:

A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

Step-by-step explanation:

A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}

det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1

A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}

A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}

Hence, confirmed

6 0
3 years ago
If a polygon is a square, then it is also a rectangle.<br><br><br> True<br><br> or <br><br> False
Art [367]

Answer:

true

Step-by-step explanation:

a square will always be a rectangle but a rectangle will not always be a square.

7 0
3 years ago
Read 2 more answers
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