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2 years ago

Find the formula for the nth term of the arithmetic sequence a1=15,d=9

Mathematics

1 answer:

sasho [114]2 years ago

8 0

The answer to this is a n = a1 + d(n - 1)

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What value of x will make triangles ABM and DCM congruent? 3 5 7 9

kykrilka [37]

The congruent side is going to be 9

6 0

2 years ago

Complete the table Original Price:? Percent of Discount: 25% Sale Price: $40

BigorU [14]

Answer:

The original price would be 50$.

Step-by-step explanation:

To find this answer you have to divide 25% by 100, which equals 0.25. Now multiply 0.25 by 40 and you get 10$. Since 10$ was the discount, you just add 10$ + 40$, therefore 50$ is the original price.

8 0

3 years ago

What is the true solution In 20+In 5=2 In x?

S_A_V [24]

Answer:

x = 10

Step-by-step explanation:

Using the rules of logarithms

• log x + log y ⇔ log(xy)

• log $x^{n}$ ⇔ n log x

• log x = log y ⇒ x = y

Given

ln20 + ln5 = 2 lnx , then

ln(20 × 5) = ln $x^{2}$

ln 100 = ln $x^{2}$ , hence

x² = 100 ( take the square root of both sides )

x = 10

7 0

3 years ago

Find the inverse of ????−7 −2

Masja [62]

Answer:

$A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

Step-by-step explanation:

$A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}$

$det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1$

$A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}$