Radius is half of the diameter so it's 7 for the diameter.
5/9 to chose odd card, 3/6 to roll even number
x+y = 47
x-y = 21
------------ add together
2x =68 divide by 2
x=34
x+y = 47
34+ y = 47
subtract 34 from each side
y = 13
the two numbers are 34 and 13
<u>Domain</u><u>~</u><u> </u>

<u>Range</u><u>~</u><u> </u>
<u>
</u>
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>:</em><em>)</em>
Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.
For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- Two children, hence
. - Equally as likely to be a boy or a girl, hence
.
The probability of one of each is P(X = 1), hence:


0.5 = 50% probability of selecting a two-child family with one boy and one girl.
A similar problem is given at brainly.com/question/24863377