3 years ago

Help Please.. Question in the file.

Mathematics

1 answer:

Romashka [77]3 years ago

4 0

How do I answer them

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The floor of a triangular room has an area of 32 1/2 sq.m. If the triangle’s altitude is 7 172 m, write an equation to determine

sineoko [7]

Answer:

$\frac{(2)A}{h} =b$

b=0.00906m

Step-by-step explanation:

Hello! To solve this exercise we must remember that the area of any triangle is given by the following equation

$A=\frac{bh}{2}$

where

A=area=32.5m^2

h=altitude=7172m

b=base

Now what we should do take the equation for the area of a rectangle and leave the base alone, remember that what we do on one side of the equation we must do on the other side to preserve equality

$A=\frac{bh}{2} \\\frac{2}{h} A=\frac{bh}{2} \frac{2}{h} \\$

$\frac{A(2)}{h} =b$

solving

$\frac{2(32.5)}{7172} =0.0090[tex]\frac{A(2)}{h} =b\\b=0.00906m$

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3 years ago

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Salsk061 [2.6K]

Answer:- 1/2

Step-by-step explanation:

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