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AnnZ [28]
3 years ago
7

. The regular price of a scooter is $89.99. The scooter is on sale for 20%

Mathematics
1 answer:
Artyom0805 [142]3 years ago
3 0

Answer:

80

Step-by-step explanation:

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Find EXACT area of regular hexagon (keep in radical form)
pickupchik [31]

Answer:

1. 24\sqrt{3}   2. 162\sqrt{2}

Step-by-step explanation:

1. The area of a hexagon is A = \frac{3\sqrt{3} }{2} a^{2}

Here our a is 4, so plugging in 4 to our equation gives \frac{3\sqrt{3} }{2} (4^{2}) which simplifies to 24\sqrt{3}

2. The area of an octagon is 2\sqrt{2} r^{2}

Here our r is 9, so plugging in 9 to our equation gives 2\sqrt{2} (9^{2} ) which simplifies to 162\sqrt{2}

6 0
4 years ago
Select all expressions to 6x-24​
Strike441 [17]

Answer:

it's the first one and the third one

Step-by-step explanation:

cause 6 (X - 4) multiply by 6 by X and 4

and same for the third expression.

8 0
3 years ago
Read 2 more answers
HELP ME PLEASEEEE<br><br> thank you &lt;3
inn [45]

Answer: 7

Step-by-step explanation: :)

5 0
3 years ago
Which expression correctly shows the difference between the product of 11 and 7 and the sum of 6 and 10?
Minchanka [31]

9514 1404 393

Answer:

  d: (11×7) - (6 + 10)​

Step-by-step explanation:

"the product of 11 and 7" is 11×7.

"the sum of 6 and 10" is (6 +10).

The difference between the product and the sum is ...

  (11×7) -(6 +10) . . . . . matches choice D

5 0
3 years ago
What is the domain of the function?
ivann1987 [24]
For a radical with an even root, like 2 in this case, if the radicand turns to a negative value, the result is just an imaginary value, which is another way to say, there's no such a root, no solution per se.

for that, let's first check when the radicand turns to 0 first.

\bf -8x+8=0\implies -8x=-8\implies x=\cfrac{-8}{-8}\implies \boxed{x=1}

so, that happens when x = 1, -8(1) +8, is just -8+8 or 0, ok.

so.. if "x" goes a bit higher, like say 2, -8(2) + 8 --> -16 + 8 --> -16

you'd get a negative value, and the radical doesn't have a root for that.

so... the domain, or values "x" can safely take without making the square root expression a negative value, are 1 or below, for example, if we use say -5

-8(-5) + 8 --> 40+8 --> 48  <------ a positive value

thus, (-∞, 1]
8 0
3 years ago
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