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2 years ago

. The regular price of a scooter is $89.99. The scooter is on sale for 20%

Mathematics

1 answer:

Artyom0805 [142]2 years ago

3 0

Answer:

Step-by-step explanation:

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If you want 10 points answer this its easy

alexgriva [62]

Answer:

1; 3; 9; 27, 81

-15; -8; -1; 6; 13

1/2; 1/4; 1/8; 1/16; 1/32

Step-by-step explanation:

Hope This Helps!

Thanks For the 5 points ; )

6 0

2 years ago

Law of cosines: a2 = b2 + c2 – 2bccos(A) Which equation correctly applies the law of cosines to solve for an unknown angle measu

Cloud [144]

The law of cosines is used for calculating one side of the triangle if the angle opposite to that side is given as well as the other sides. For this problem, we are given angle B. Therefore, the correct answer among the choices given is option 1 where a is equal to 5 and c is equal to 3.

8 0

3 years ago

Read 2 more answers

Which value is equivalent to ( 7 • 5 • 2 over 7 • 3) ^2 • ( 5^0 over 2^-3) ^3 • 2^-9

ser-zykov [4K]

100 / 9

They both equal 11.11
(70/21)^2 * 8^3 * (1/2^9)

3 0

3 years ago

In a survey of 400 seniors, x percent said that they plan on majoring in physics. One university has used this data to estimate

azamat

Answer:

2 percent

Step-by-step explanation:

We can use two separate fractions, one representing the amount of physics majors expected and the amount of seniors expected in physics majors by the university.

$\frac{400x}{66} = \frac{400}{3600}$

Now cross multiply.

$\frac{66*400}{400x * 3600}$

x will be removed.

$\frac{26400}{1320000}$

Simplifying this fraction will get you $\frac{1}{50}$ , which in percentage form, will be 2 percent.

8 0

1 year ago

What is the distance between nicholas's school and the post office?

aleksklad [387]

Part A:

Given that Nicholas's school is located at point (3, 2) and that the post office is located at point (-2, -2), then the distance between Nicholas's school and the post office is given by:

$d= \sqrt{(-2-3)^2+(-2-2)^2} \\ \\ = \sqrt{(-5)^2+(-4)^2} = \sqrt{25+16} \\ \\ \sqrt{41} =\bold{6.4} \ units$

Part B:

If Nicholas is located at point (– 3 , 2), the distance to get to the grocery store located at point (1,-1) is given by:

$d= \sqrt{(1-(-3))^2+(-1-2)^2} \\ \\ = \sqrt{(1+3)^2+(-3)^2} = \sqrt{(4)^2+9} \\ \\ = \sqrt{16+9} = \sqrt{25} =\bold{5}$

4 0

3 years ago