ΔAOB is a right angled triangle. Therefore the Pythagorean Theorem applies in this situation.
θ is the angle from a standard position of the line OA
The length of the y component is √(1-0)2 +(-3-(-3))2] =√(12+ 02) = 1 A(-3,1) to B(-3,0) which is opposite
Then the length of the x-component is √[(-3-0)2 +(0-0)2] = √(9+0)= 3 B(-3,0) to O(0,0) which is adjacent
The length of vector OA is √[(-3-0)2 + (1-0)2] = √(9+1) = √(10) A(-3,1) to O(0,0) which is the hypotenuse of the triangle
θ = 180 - α
sinθ = sin(180-α) = opposite/hypotenuse = 1/√10
cosθ = adjacent/hypotenuse = -3/√10
tanθ = opposite/adjacent = 1/-3 = -1/3
α= arcsin(1/√10) ≈ 18
θ =180 -18 ≈162
Answer:
x = 18/5
Step-by-step explanation:
7x + 4 = 2x+ 22
5x = 18
x = 18/5
Answer:
16.5
Step-by-step explanation:
this is beacuse 16.5 times 2 is 33
Answer: The dimensions are 8 and 3
Step-by-step explanation:
So 8*3=24 which corresponds with the formula for area l*w= Area
And perimeter means we add up all 4 sides so
8+8+3+3= 22
So the dimensions are 8 and 3
Answer:
x = 10 units
Step-by-step explanation:
16 is to 40 as x+2 is to 3x
16/40 = (x+2) / 3x
48x = 40x + 80
8x = 80
x = 10
