I attached the question. I will give brailiest if correct. I promise.
1 answer:
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Answer:
B) -3
Step-by-step explanation:
The zeros of the function are found easily from the factors. They are 6 and -12. The x-coordinate is halfway between them, at (6 + (-12))/2 = -6/2 = -3.
If you want a formula, consider a quadratic with roots (zeros) p and q. Then it factors as
... y = (x -p)(x -q)
The line of symmetry through the vertex is also the line of symmetry between the roots, so has x-coordinate:
... x = (p+q)/2
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In your problem, you have p=6, q=-12, so x = (p+q)/2 = -6/2 = -3 is the line of symmetry and the x-coordinate of the vertex.
