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Pavel [41]
3 years ago
6

What percentage of a group of students plays at least one sport if two-fifths of the group plays at least one sport?

Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0
3
2/5= 0.40
.40=40%
40% is final answer
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CaHeK987 [17]
Yes, they are all per something so yes
7 0
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Please answer i wanna get this over with h ^-2 / h ^4
Svetllana [295]

Answer:

= h^-6

Step-by-step explanation:

When dividing powers you subtract them (indices rules)

--> -2 - 4 = -6

Hope this helps, please mark as brainliest

5 0
3 years ago
Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua
goblinko [34]
<h2>Hello!</h2>

The answer is:  There is a total of 5.797 gallons pumped during the given period.

<h2>Why?</h2>

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

D(t)=\frac{5t}{1+3t}

So, the integral will be:

\int\limits^4_0 {\frac{5t}{1+3t}} \ dx

So, integrating we have:

\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx

Performing a change of variable, we have:

1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}

Then, substituting, we have:

\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du

\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )

\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du

\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]

Reverting the change of variable, we have:

\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]

Then, evaluating we have:

\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0
4 years ago
Cuáles de los siguientes experimentos son aleatorios. a) Número de personas que suben a un autobús en una parada. b) Aplicar el
ivanzaharov [21]

Answer:

<h2>a) Número de personas que suben a un autobús en una parada.</h2><h2>c) Conocer el ganador de la Liga de Campeones.</h2>

Step-by-step explanation:

This problem is about random experiments.

Random experiments are defined as experiments where the outcome can't be predicted. To ensure that result, the subjects are selected randomly. So, in this case, the right answer must be a situation where subjects are randomly present.

People taking the bus is a random experiment, because there's no the exact subjects in a bus at any time, it happens randomly.

Also, the winner of a sport league is also a random experiment, because it happens after several games which cannot be predicted.

Therefore, the right answers are a and c.

5 0
3 years ago
I will mark brainiest , I'm giving out my points so hurry!<br> Would you rather
Fed [463]

Answer:

Cube 1

Step-by-step explanation:

Volume of cube 1

V = 25*25*25 = 15625


Volume of 2 cubes

V = 24*24*24 = 13824

V =7*7*7 =343

V total = 14167


The total volume is greater for the 1 cube

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