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ehidna [41]
3 years ago
12

Two students, Ann and Max, factored the trinomial 4x2-6x -4. Ann factored it as 2(k 2xx+ 1) and Max factored it as (-2)4x+2), In

dicate which student factored the trinomial completely and which student did not, and explain why.
Mathematics
1 answer:
marishachu [46]3 years ago
8 0

Given trinomial 4x^2-6x-4.

In order to factor a trinomial, we need to factor out greatest common factor (GCF).

In the given trinomial, we have terms 4x^2, -6x, -4.

We can see that all terms can be divided by a greatest number 2.

Therefore, greatest common factor would be 2 there.

We need to factor out 2 first.

On factoring out 2, we get

2(2x^2 -3x -2).

Now, we need to factor out trinomial 2x^2 -3x -2 now.

We can factor a trinomial by applying product sum rule.

We have a=2,b=-3,c=-2.

ac= 2*-2 = -4 and b=-3.

So, we need to find the factors of -4 that add upto -3.

Factors of -4 would be -4 and 1.

Let us replace -3x by -4x +1x in 2x^2 -3x -2 trinomial

2x^2 -3x -2 could be rewrite as 2x^2 -4x +1x -2.

Making it into two groups and factoring out GCF of each group.

We get

(2x^2 -4x) +(1x - 2)

2x(x-2) +1(x-2)

=(x-2)(2x+1)

Therefore, final factors of the trinomial is 2(x-2)(2x+1).

So, Ann factored form 2(x-2)(2x+1) is correct.

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The five circles making up this archery target have diameters of length $2,4,6,8,$ and $10$. What is the total red area?
Sliva [168]

Answer:

A=15\pi\ units^2

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

It is given that the diameter of 5 circles making up the archery is 2,4,6,8, and 10.

To determine the total red area, we use the formula for area of the circle

A=\pi r^{2}

step 1

Find the Area of the 1st red circle

r=2/2=1\ unit ---> the radius is half the diameter

A_1=\pi (1)^{2}=\pi\ units^2

step 2

Find the Area of the 2nd white circle

r=4/2=2\ units ---> the radius is half the diameter

A_2=\pi (2)^{2}=4\pi\ units^2

step 3

Find the Area of the 3rd red circle

r=6/2=3\ units ---> the radius is half the diameter

A_3=\pi (3)^{2}=9\pi\ units^2

step 4

Find the Area of the 4th white circle

r=8/2=4\ units ---> the radius is half the diameter

A_4=\pi (4)^{2}=16\pi\ units^2

step 5

Find the Area of the 5th red circle

r=10/2=5\ units ---> the radius is half the diameter

A_5=\pi (5)^{2}=25\pi\ units^2

The total red area is given by

A=A_5-A_4+A_3-A_2+A_1

substitute

A=25\pi-16\pi+9\pi-4\pi+\pi

A=15\pi\ units^2

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Answer:

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I don’t understand this question
Arada [10]

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step 1. a polynomial must have whole non negative exponents

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