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Sidana [21]
3 years ago
13

Is it true that if two angles with measures that sum to 180 that they are linear pairs?

Mathematics
2 answers:
ddd [48]3 years ago
7 0
Yes, it is true that if 2 angles with measures that sum to 180 they are linear

inna [77]3 years ago
4 0
If<span> it is perfectly clear which angle is being named, an angle may be referred to by its ... Supplementary Angles are </span>2 angles<span> the </span>sum<span> of whose </span>measures<span> is </span>180<span>°. ... THEOREM: </span>If<span> two congruent angles form a </span>linear pair<span>, </span>they<span> are right angles.</span>
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In a naval engagement, one-third of the fleet was captured, one-sixth was sunk, and two ships were destroyed by fire. One-sevent
Otrada [13]

Answer:

60 ships.

Step-by-step explanation:

Let the total number of ships in the naval fleet be represented by x

One-third of the fleet was captured = 1/3x

One-sixth was sunk = 1/6x

Two ships were destroyed by fire = 2

Let surviving ships be represented by y

One-seventh of the surviving ships were lost in a storm after the battle = 1/7y

Finally, the twenty-four remaining ships sailed home

The 24 remaining ships that sailed home =

y - 1/7y = 6/7y of the surviving fleet sailed home.

Hence

24 = 6/7y

24 = 6y/7

24 × 7/ 6

y = 168/6

y = 28

Therefore, total number of ships that survived is 28.

Surviving ships lost in the storm = 1/7y = 1/7 × 28 = 4

Total number of ships in the fleet(x) =

x = 1/3x + 1/6x + 2 + 28

Collect like terms

x - (1/3x + 1/6x) = 30

x - (1/2x) = 30

1/2x = 30

x = 30 ÷ 1/2

x = 30 × 2

x = 60

Therefore, ships that were in the fleet before the engagement were 60 ships.

3 0
3 years ago
I don't know how to do this
vesna_86 [32]
He could have 30 dimes and 13 quartars
7 0
3 years ago
One person is selected at random from a class of 20 males and 13 females. Find the odds against selecting a male and a female
spin [16.1K]

Answer:

Odds for male= 1.538

Odds for female =  0.65

Step-by-step explanation:

The question is asking for odds, not a probability. A probability shows how much the chance for the event to happen, so it can be expressed as a percentage. Odds show how the event more likely to happen compared to the chance it did not happen. If an event has a 90% probability, the odds will be 90:10= 9

In this case, the odds of selecting a male will be:  

number of male : number of female= 20:13 = 1.538

The odds of selecting a female will be

number of female : number of male = 13/20 = 0.65

7 0
3 years ago
Find the missing coordinate to complete the ordered-pair solution to the given linear equation: 3x-4y=6
zavuch27 [327]
8 is the answer if u do some equation gymnastics as i call them
8 0
3 years ago
Suppose the heights of a population of people are normally distributed with a mean of 65.5 inches and a standard deviation of 2.
kupik [55]

Answer:

a) P(64.2

b) 69.764

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(65.5,2.6)

Where \mu=65.5 and \sigma=2.6

We are interested on this probability

P(64.2

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(64.2

And we can find this probability on this way:

P(-0.50

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

P(-0.50

3) Part b

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.05   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64. On this case P(Z<1.64)=0.95 and P(z>1.64)=0.05

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.64

And if we solve for a we got

a=65.5 +1.64*2.6=69.764

So the value of height that separates the bottom 95% of data from the top 5% is 69.764.

5 0
3 years ago
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