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tresset_1 [31]
3 years ago
7

Using the graph of f(x) below, find limit as x approaches negative 1 of f of x. (4 points)

Mathematics
1 answer:
Rama09 [41]3 years ago
7 0

Answer:

The limit of the function as x approaches to -1, is -1 and the option 4 is correct.

Step-by-step explanation:

According the the definition of limit, if,

L=\lim_{x\rightarrow a^+}f(x)=\lim_{x\rightarrow a^-}f(x)

Then the limit of function exist. Either the function is defined or not on the point a. If the at point a the value value of function is L, then the function is continuous.

From the given graph it is easily noticed that the value of f(x) approaches to -1 as x approaches to -1 from left or left. At x=-1 there is a open circle on (-1,-1), therefore this is not included in the function.

The value of f(x) is 2 at x=-1 because of the point (-1,-2).

\lim_{x\rightarrow -1^+}f(x)=\lim_{x\rightarrow -1^-}f(x)=-1

Therefore the limit of the function exist and the limit of the function is -1.

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Two of your friends, Matt and Karen, both run to you to settle a dispute. They were working on a math problem, and got different
Anna11 [10]
So in matt's equation, he made a mistake in the a transision from line 2 to line 3 
in line 2:  -4(-2)2
in line 3: -4(4) 
the mistake is that -2 times 2 is not equal +4 it is equal to -4
also from lines 5 to 6 he made a mistake in order of opperations (mulit division then addition and subtract)
line 5: -10+30/5
line 6: 20/5

so he first subtracted 10 then divided, he should have divided then subtracted
so the equation should have equaled 

Karen used the correct (-) times (+) property and the order of operations
so Karen is correct and Matt is wrong.

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3 years ago
Read 2 more answers
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Nostrana [21]

Answer:

<h2>C</h2>

Step-by-step explanation:

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3 years ago
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A card is drawn from a standard deck. What is the probability that the card is a 6 OR a 10?
hodyreva [135]

Answer:

uh

Step-by-step explanation:

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7 0
3 years ago
Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=
jasenka [17]

Answer:

The function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

\\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

The function is continuous at point x=36 if:

  1. The function \\ f(x) exists at x=36.
  2. The limit on both sides of 36 exists.
  3. The value of the function at x=36 is the same as the value of the limit of the function at x = 36.

Therefore:

The value of the function at x = 36 is:

\\ f(36) = \frac{36*\sqrt{36}}{(36-6)^{2}}

\\ f(36) = \frac{36*6}{900} = \frac{6}{25}

The limit of the \\ f(x) is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

\\ lim_{x \to 36} f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}}

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Since

\\ f(36) = \frac{6}{25}

And

\\ \lim_{x \to 36} f(x) = \frac{6}{25}

Then, the function \\ f(x) = \frac{x*\sqrt{x}}{(x-6)^{2}} is continuous at x = 36.

8 0
3 years ago
Will give 17 points, brainliest and 5 star rating. Plz help me
yKpoI14uk [10]

Answer:

Try to make coordinate plane in head and plot in there or use a graoh paper and do your coordinate grid

Hope I helped!

5 0
4 years ago
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