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3 years ago

Caleb blanket is 7 feet long and 7 Feet wide. Haley blanket is 6 feet long and 5 feet wide

Mathematics

1 answer:

Vinvika [58]3 years ago

8 0

What do you need to know??

You might be interested in

What is the area of this figure?

sweet-ann [11.9K]

Answer:

38.5

Step-by-step explanation:

to find the area of the triangle, you can do 11 x 3 ÷ 2 = 16.5

then you find the area of the triangles: 3 x 3 = 9

and 3 × 11 = 33

then you add them all to find a total area of 38.5

5 0

3 years ago

Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)(t^2-2t+2)\,\mathrm dt$

Complete the square in the quadratic term of the integrand: $t^2-2t+2=(t-1)^2+1=(1-t)^2+1$ , then in the integral we substitute $u=1-t$ :

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt$

$\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du$

Make another substitution of $v=u^2$ :

$\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv$

Integrate by parts, taking

$r=v+1\implies\mathrm dr=\mathrm dv$

$\mathrm ds=e^v\,\mathrm dv\implies s=e^v$

$\displaystyle=-e^v(v+1)\bigg|_{v=0}^{v=1}+\int_{v=0}^{v=1}e^v\,\mathrm dv$

$\displaystyle=-(2e-1)+(e-1)=-e$

So, we have by the fundamental theorem of calculus that

$\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)$

$\implies-e=f(1,1,1)-2$

$\implies f(1,1,1)=2-e$

3 0

3 years ago

Find the consecutive positive odd integers whose product is 99

dezoksy [38]

Answer:

9 and 11

Step-by-step explanation:

So let's say that the first integer is x.

That means that the second integer is x+2, since it us the next odd number.

This problem can be easily solved with our mind the answer is 9 and 11, but I'll show you the steps to slove this.

We make an equation using these two numbers:

$(x)*(x+2)=99\\$

Now all we gotta do is solve for x:

$x^2 +2x = 99\\x^2+2x-99=0$

Now we use either splitting the middle term or quadratic formula:

$x^2+11x-9x+99=0\\x(x+11)-9(x+11)=0\\(x+11)(x-9)=0$

Now we split each terma and solve for x:

$(x-9)=0\\x=9\\(x+11)=0\\x=-11$

Now the question states <em>positive </em>so we can rule out x = -11.

Now we have the first integer x = 9,

the second integer is x+2 = 9+2 =11

So the two consecutive positive odd integers are 9 and 11

4 0

3 years ago

Pls help if your kind <3 (picture)

AlladinOne [14]

Answer:

1: x=23.313708 2: B x = -13.2 3: x = 152

All the problems examples at the bottom

Step-by-step explanation:

1: 12x=−3(4−x)

12x=3x−12

Step 1: Divide both sides by 12.

12x12=3x−1212

x=14x−1

Step 2: Solve Square Root.

x=14x−1

x=(14x−1)2(Square both sides)

x=116x2+−12x+1

x−(116x2+−12x+1)=116x2+−12x+1−(116x2+−12x+1)(Subtract 1/16x^2+(-1)/2x+1 from both sides)

−116x2+32x−1=0

x=−b±b2−4ac2a(Use quadratic formula with a=-0.0625, b=1.5, c=-1)

x=−(1.5)±(1.5)2−4(−0.0625)(−1)2(−0.0625)

x=−1.5±2−0.125

x=0.6862915010152388,23.31370849898476

2: 3+2.7x=9.6+3.2x

Step 1: Simplify both sides of the equation.

2.7x+3=3.2x+9.6

Step 2: Subtract 3.2x from both sides.

2.7x+3−3.2x=3.2x+9.6−3.2x

−0.5x+3=9.6

Step 3: Subtract 3 from both sides.

−0.5x+3−3=9.6−3

−0.5x=6.6

Step 4: Divide both sides by -0.5.

−0.5x−0.5=6.6−0.5

x=−13.2

3: 9+34x=78x−10

Step 1: Simplify both sides of the equation.

9+34x=78x−10

9+34x=78x+−10

34x+9=78x−10

Step 2: Subtract 7/8x from both sides.

34x+9−78x=78x−10−78x

−18x+9=−10

Step 3: Subtract 9 from both sides.

−18x+9−9=−10−9

−18x=−19

Step 4: Multiply both sides by 8/(-1).

(8−1)*(−18x)=(8−1)*(−19)

x=152

I really hope this helped you

4 0

3 years ago

$2500 in saving account earing 3,5 perccent interest. what was the the total interest earnedin 6 years

Dvinal [7]

Answer:

$I=\$525$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=6\ years\\ P=\$2,500\\r=3.5\%=3.5/100=0.035$

substitute in the formula above

$I=\$2,500(0.035*6)$

$I=\$525$

8 0

3 years ago