Question

Perform the indicated operation g(x)=-x-3 h(x) = x 2+X Find (goh) (x)​

Answer 1

Answer:

Step-by-step explanation:

h(x) = x^2 + x

g(x^2 + x)

-(x^2 + x) - 3

-x^2 - x - 3

Answer 2

Answer:

$(g\circ h)(x)=-x^2-x-3$

Step-by-step explanation:

So we have the two functions:

$g(x)=-x-3\text{ and } h(x)=x^2+x$

And we want to find:

$(g\circ h)(x)$

This is the same thing as:

$=g(h(x))$

So, substitute h(x) into g(x):

$g(x)=-x-3\\g(h(x))=-(x^2+x)-3$

Distribute the negative:

$g(h(x))=-x^2-x-3$

And we're done!

So:

$(g\circ h)(x)=-x^2-x-3$