The line x - y = 5 passes through the point (0, -5)
Answer:
The correct option is:
h = 1, k = 16
Step-by-step explanation:
y=4x^2-8x+20 =0
It is a quadratic formula in standard form:
ax^2+bx+c
where a = 4 , b = -8 and c=20
The vertex form is:
a(x − h)2 + k = 0
h is the axis of symmetry and (h,k) is the vertex.
Calculate h according to the following formula:
h = -b/2a
h= -(-8)/2(4)
h = 8/8
h = 1
Substitute k for y and insert the value of h for x in the standard form:
ax^2+bx+c
k = 4(1)^2+(-8)(1)+20
k = 4-8+20
k=-4+20
k = 16
Thus the correct option is h=1, k=16....
I think the domain and range are infinite
You just have to look at the form of the equations
The only linear equations would be y = mx + b and Ax + By = C
Answer:
6y + 5x = -54
Step-by-step explanation:
y = m x + b -> slope-intercept form
ax + by = c -> standard form
6y = -5x - 54
6y + 5x = -54
