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Stolb23 [73]
3 years ago
13

A car is driving at 40 kilometers per hour. How far in meters does it travel in 4 seconds

Mathematics
1 answer:
harina [27]3 years ago
4 0
It’s most likely 160meters
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The equation of line p is y=ax+b. Which of these could be the equation of line q? A.y=−3a(x+6)+b
Ilia_Sergeevich [38]
The slope of line q is that of line p scaled by a factor of 3 (not -3). The y-intercept of line q is 6 less than the y-intercept of line p. The appropriate choice is
  D. y = 3ax +b -6
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3 years ago
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25 Points!! The graph represents the first three terms in an arithmetic sequence.
Drupady [299]

Answer:

Step-by-step explanation:

y-1=\frac{4-1}{2-1}(x-1)\\y-1=3(x-1)\\y=3x-3+1\\y=3x-2

b.

an=an-1+3

C.

when x=15

y=3×15-2=45-2=43

a15=43

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The height of Maury’s room is 8.4 feet from the floor to the ceiling. Maury wants to install a ceiling fan that hangs 1.875 feet
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find the equation of the circle where (-9,4),(-2,5),(-8,-3),(-1,-2) are the vertices of an inscribed square.
solniwko [45]
Check the picture below, so, that'd be the square inscribed in the circle.

so... hmm the diagonals for the square are the diameter of the circle, and keep in mind that the radius of a circle is half the diameter, so let's find the diameter.

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\stackrel{diameter}{d}=\sqrt{[-8-(-2)]^2+[-3-5]^2}
\\\\\\
d=\sqrt{(-8+2)^2+(-3-5)^2}\implies d=\sqrt{(-6)^2+(-8)^2}
\\\\\\
d=\sqrt{36+64}\implies d=\sqrt{100}\implies d=10

that means the radius r = 5.

now, what's the center?  well, the Midpoint of the diagonals, is really the center of the circle, let's check,

\bf \textit{middle point of 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{-8-2}{2}~,~\cfrac{-3+5}{2} \right)\implies (-5~,~1)

so, now we know the center coordinates and the radius, let's plug them in,

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&-5&1&5
\end{array}
\\\\\\\
[x-(-5)]^2-[y-1]^2=5^2\implies (x+5)^2-(y-1)^2=25

8 0
3 years ago
Find the perimeter and area of the figure.
Jobisdone [24]
The area is 36 and the perimeter is 26
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