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Bas_tet [7]
3 years ago
8

What is the simplified form of the expression k^3(K^7/5)^-5

Mathematics
1 answer:
Vladimir79 [104]3 years ago
3 0
\bf k^3\left( \cfrac{k^7}{5} \right)^{-5}\implies k^3\left( \cfrac{5}{k^7} \right)^5\implies k^3\left( \cfrac{5^5}{k^{7\cdot 5}} \right)\implies k^3\cdot \cfrac{5^5}{k^{35}}
\\\\\\
k^3\cdot 5^5\cdot k^{-35}\implies 5^5\cdot k^{3-35}\implies 5^5k^{-32}\implies \cfrac{5^5}{k^{32}}\implies \cfrac{3125}{k^{32}}
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When Imani walks to school, it takes her one less minute than five times the amount of time it takes her to ride her bike to sch
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The numerical expression that describes the amount of time it takes Imani to walk to school is x = 5y - 1.

<h3>How do we derive a numerical expression?</h3>

Let:

x = amount of time it takes Imani to walk to school

y = amount of time it takes Imani to ride to school = 3 minutes

The numerical expression that describes the amount of time it takes Imani to walk to school can be written as follows:

x = 5y - 1

Since it takes Imani three minutes to ride her bike to school, we can solve for x by substituting y = 3 as follows:

x = (5 * 3) - 1 = 15 - 1 = 14 minutes

Learn more about a numerical expression here: brainly.com/question/14642484.

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6 0
2 years ago
What is the answer for this
Georgia [21]
The domain is all real numbers
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3 years ago
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Andre45 [30]
The answer 
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let's consider axis
y'y  </span>vectF = -F
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3 years ago
Fill in the blank _+8=+6<br> And chose the property of addition you send
Paha777 [63]

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3 years ago
A certain mathematics contest has a peculiar way of giving prizes. Five people are named as Grand Prize winners, but their finis
bixtya [17]

Answer:

The number of complete award announcements possible are 19,554,575,040.

Step-by-step explanation:

Combination is the number of ways to select <em>k</em> items from <em>n</em> distinct items when the order of selection does not matters.

Whereas permutation is the number of ways to select <em>k</em> item from <em>n</em> items when order of selection matters.

The number of people entering this year is 22.

The number of ways to select 5 people for Grand Prize is, {22\choose 5}=\frac{22!}{5!(22-5)!} =26334.

The remaining number of people is, 22 - 5 = 17.

It is provided that the other 5 are selected according to an order.

The number of ways to select other 5 winners is,

^{17}P_{5}=\frac{17!}{(17-5)!} =742560

The total number of ways to select 10 winners of 22 is:

Total number of ways = 26334 × 742560 = 19,554,575,040.

6 0
3 years ago
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