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3 years ago

PLEASE HELP FIRST ONE IS QUESTION THE REST ARE CHOICES Which expression is equivalent to

Mathematics

1 answer:

Readme [11.4K]3 years ago

8 0

$\sqrt[3]{256x^{10}y^7} = \sqrt[3]{4^3*4*x^{9}*x*y^6*y} = 4x^3y^2(\sqrt[3]{4xy})$

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HELP!!!!!!!

igomit [66]

Substituting the data points into the model:

f(x)= -x2 + 2x -3

f(-2)=-11

f(0)=-3

f(1)=-2

f(3)=-6

f(5)=-18

So A is the right ans.

7 0

3 years ago

Read 2 more answers

A car travels 182 kilometers in 4 hours with the constant speed. how much time will it take traveling 42 kilometers

Schach [20]

Answer:

55.38 min

Step-by-step explanation:

A car travels,

182 km ⇒ 4 hours

And we have to find the time that it takes to travel 42 km .

Lets make a equation.

Let the unknown time be x

182 km ⇒ 4 hours

42 km ⇒ x

To make easy let's km in to meters and hours in to minutes

182000 m ⇒ 240 min

42000m ⇒ x

Now use cross multiplication.

$182000x=240*42000\\$

$182000x=10080000$

$\frac{182000x}{182000} =\frac{1008000}{182000}$

$x =55.38min$

Hope this helps you.

Let me know if you have any other questions :-)

6 0

2 years ago

If f(x) = 16x-30 and g(x) = 14(x)-6 for which value of x does (f-g) (x) = 0

almond37 [142]

This is a system where (f-g)(x) is wanted.
(16x-30)-(14x-6) .... 2x-24 *be careful with signs and parenthesis placement.

Now set 2x-24 = 0 and so x = 12

6 0

3 years ago

Plz help me !!!!!!!!!!!

Artist 52 [7]

Split the second term in 3a^2 - 8a + 4 into two terms

3a^2 - 2a - 6a + 4 = 0

Factor out common terms in the first two terms, then in the last two terms.

a(3a - 2) -2(3a - 2) = 0

Factor out the common term 3a - 2

(3a - 2)(a - 2) = 0

Solve for a;

a = 2/3,2

<u>Answer : B. (2/3,2)</u>

6 0

3 years ago

Y=-2x²-8x-5 domain and range

Jobisdone [24]

Answer:

Domain: All real numbers

Range: y≤3

Step-by-step explanation:

The given function is

$y = - 2 {x}^{2} - 8x - 5$

This is a polynomial function.

The domain is set of all values of x, that makes this function defined.

Since polynomial functions are defined everywhere, the domain is all real numbers.

To find the range we put the function in vertex form:

$y = - 2( {x}^{2} + 4x) - 5$

$y = - 2( {x}^{2} + 4x + 4) - 5 + - 4 \times - 2$

$y = - 2( {x} + 2)^{2} - 5 + 8$

$y = - 2( {x} + 2)^{2} + 3$

The maximum value is 3

The function turns downward, hence the range is:

$y \leqslant 3$

6 0

3 years ago