T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
2) EF is congruent to OP
3) angle P is congruent to angle F
4) angle G is congruent to angle Q (that weird upside down parentheses, I think that is a Q)
5) measure of angle O equals 110 degrees and it equals the measure of angle E
6)QO equals GE and it is 7km
7) triangle GFE is congruent to triangle QPO
What you would do is start crossing the highest and lowest values off on both sides of the chart until you had one or two remaining.
Once that is done, you'll be able to determine the median.
The median in this case is 2.
Hope this helps!
Cat= 6kg
Dog = 6kg + 22kg
Total weight = 6kg + 6kg + 22kg
Total weight = 34kg
